Answer:
You could prove that ΔAMC and ΔBMD are congruent by AAS
Step-by-step explanation:
Step 1: Given
step 2: Vertical Angles Thm (the two triangles connect at a point)
Step 3: AAS (This is because segment AC is congruent to segment BD, Angle A is congruent to angle B, and ∠AMC is congruent to ∠BMD making the triangles congruent by Angle angle side.
Step 4: CPCTC
Hope I helped! And plus... LA is not a Congruence theorem and It would not be HL because there is only one congruent side given.
Answer:
A = 
Step-by-step explanation:
given,
Matrix =
A = 
determinant of matrix
|A| = a×a - (a-4)(a+4)
|A| = a² - a² +16
|A| = 16
inverse of the matrix
to calculate inverse of two matrix interchange the term a₁₁ with a₂₂ and multiply the -ve with a₁₂ and a₂₁
the inverse is
A =
140,000. the hundred is under 5 so you round down
I believe it would be true.
However remote interior angles are formed on the outside of a triangle when a side is extended beyond the vertex, not triangle.
