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3 years ago

5

Teacher takes about 25 minutes to make out a test for a mathematics class. How long will it take to make out tests for all five

classes?

1 answer:

Akimi4 [234]3 years ago

6 0

Answer:

2h 5min

Step-by-step explanation:

1 class: 25 min

5 classes: 25 x 5 = 125 min = 2h 5min

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Willie and Emily each purchase one raffle ticket. If a total of seven raffle tickets are sold, what is the probability that Will

Nimfa-mama [501]

1/42

First, find the probability of Willie winning the grand prize. He has 1 ticket out of the 7 total tickets, so the probability is 1/7.

Now, find the probability of Emily winning the second prize. After the grand prize winner has been announced, there are only 6 tickets left. Emily has 1, so the probability is 1/6.

Finally, multiply the two probabilities together to find the probability that they will both happen together. To multiply fractions, multiply the numerators together and multiply the denominators together. This leaves us with (1 * 1) / (7 * 6), which is easy to simplify to 1/42, which is the final probability.

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Help how do I solve this and how do I do it

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C. 30+18x

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Mark the statements that are true. an angle that measures pi/3 radions also measures 30 degrees

Aleks04 [339]

Answer:

Pi/3 radians also measures 60 degrees not 30

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3 years ago

The length of one base of a trapezoid is 19 less than five times the length of the other base. If the trapezoid has a height of

ycow [4]

The length of the longer base is 41 ft.

<u><em>Explanation</em></u>

Lets assume, length of one base is $x$ ft.

As, another base is 19 less than five times the length of this base, so the length of another base $= (5x- 19) ft.$

The trapezoid has a height of 18 ft and area of 477 ft²

Formula for Area of trapezoid, $A=\frac{1}{2} (a+b)*h$ , where $a, b$ = Two bases of trapezoid and $h$ = height of the trapezoid.

Given in the question: $A= 477$ and $h= 18$

We have also two bases as: $a= x$ and $b= 5x-19$

So, according to the above formula...

$A= \frac{1}{2}(a+b)h\\\\ 477=\frac{1}{2}(x+5x-19)*18\\\\ 477=9(6x-19)\\\\477= 54x-171\\\\477+171=54x\\\\648=54x\\\\x=\frac{648}{54} = 12$

So, length of one base is $12 ft$ and another base $=(5*12-19)ft =(60-19)ft = 41 ft$

That means, the length of the longer base is 41 ft.

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3 years ago