Ask question

Ask question

All categories

lisabon 2012 [21]

3 years ago

10

The diagram below shows a model of four waves. An image of four waves labeled W, X, Y, Z is shown. Wave W has the smallest dista

nce from crest to crest across the length of the wave. Wave Z has the largest distance from crest to crest across the length of the wave. Wave X has a larger distance from crest to crest than Wave W but are not as far apart as Wave Y. Wave Y has a larger distance from crest to crest than Wave X but not as far apart as Wave Z. Which wave has the lowest frequency? (1 point) a W b X c Y d Z ill give 40 brainiest

1 answer:

olya-2409 [2.1K]3 years ago

4 0

Answer:

its b

Step-by-step explanation:

You might be interested in

Se corta una manzana en 12 partes, se comen ocho partes. Qué fracción simplificada a su mínima expresión representa la cantidad

lakkis [162]

Answer:

A. 1/3

Step-by-step explanation:

Dado que:

una manzana se corta en 12 partes y se comen ocho partes.

La fracción de manzanas consumidas = 8/12

= 2/3

La fracción de manzanas que quedan = valor original de la manzana que se corta - la fracción de la manzana que se come

La fracción de manzanas que quedan $=1- \dfrac{8}{12}$

La fracción de manzanas que quedan $=\dfrac{12-8}{12}$

La fracción de manzanas que quedan $=\dfrac{4}{12}$

A la fracción más baja; obtenemos = 1/3

6 0

3 years ago

State the possible number of zeros.

sp2606 [1]

the answer to the question is

4 0

3 years ago

The number 49 has exactly three factors. Since 98 is a multiple of 49, which must be true of 98? It must have only two factors.

Mumz [18]

Answer:

Step-by-step explanation:

⇒49=7×7 =1 × 49

Factors of 49 = 1,7,49

⇒It is given that ,98 is a Multiple of 49.

98 = 49 × 2

So, apart from factors of 49, number 2, and 98 are also included in the set of factors of 98.

→Factors of 98 are =1,2,7,49,98

3 0

3 years ago

Plz hurry!!!! How do you find it?

Sloan [31]

Fine the length BC using the cosine law. Google the law and sub it in

6 0

3 years ago

The harmonic motion of a particle is given by f(t) = 2 cos(3t) + 3 sin(2t), 0 ≤ t ≤ 8. (a) When is the position function decreas

iren [92.7K]

For the last part, you have to find where $f'(t)$ attains its maximum over $0\le t\le8$ . We have

$f'(t)=-6\sin3t+6\cos2t$

so that

$f''(t)=-18\cos3t-12\sin2t$

with critical points at $t$ such that

$-18\cos3t-12\sin2t=0$

$3\cos3t+2\sin2t=0$

$3(\cos^3t-3\cos t\sin^2t)+4\sin t\cos t=0$

$\cos t(3\cos^2t-9\sin^2t+4\sin t)=0$

$\cos t(12\sin^2t-4\sin t-3)=0$

So either

$\cos t=0\implies t=\dfrac{(2n+1)\pi}2$

or

$12\sin^2t-4\sin t-3=0\implies\sin t=\dfrac{1\pm\sqrt{10}}6\implies t=\sin^{-1}\dfrac{1\pm\sqrt{10}}6+2n\pi$

where $n$ is any integer. We get 8 solutions over the given interval with $n=0,1,2$ from the first set of solutions, $n=0,1$ from the set of solutions where $\sin t=\dfrac{1+\sqrt{10}}6$ , and $n=1$ from the set of solutions where $\sin t=\dfrac{1-\sqrt{10}}6$ . They are approximately

$\dfrac\pi2\approx2$

$\dfrac{3\pi}2\approx5$

$\dfrac{5\pi}2\approx8$

$\sin^{-1}\dfrac{1+\sqrt{10}}6\approx1$

$2\pi+\sin^{-1}\dfrac{1+\sqrt{10}}6\approx7$

$2\pi+\sin^{-1}\dfrac{1-\sqrt{10}}6\approx6$

4 0

3 years ago