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vova2212 [387]
3 years ago
13

A cube has a surface area of 24. What's the volume?

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
4 0

Answer:

<h2 />

Step-by-step explanation:

The voloum is 8 cubic cm.

Hatshy [7]3 years ago
4 0

if the surface area is 24 the volume is 8.

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PLEASE ANSWER ASAP!!!
adell [148]

Answer:

A

Step-by-step explanation:

100fps=68.182mph

68.182/3.8=17.94

8 0
3 years ago
Completing the sqaure <br> x^2+14x+34
DiKsa [7]

Answer:

-7-√15

Step-by-step explanation:

First move the constant to the right hand side and change it's sign

x^2+14x=-34

Then add (14/2)^2 or 7^2 to both sides

x^2+14x+49=-34+49

Then factor the expression

(x+7)^2=-34+49

Then solve (x+7)^2=15

You should get:

x=-√15-7

or

x=√15-7

7 0
3 years ago
Solve the inequality 6x - 2(x + 1) &gt; 0
castortr0y [4]
The answer would be 2 > 0.
4 0
3 years ago
The volume of a gift box is 972 in. The height of the gift box is 12 inches
Serggg [28]

Answer:

The length of each side of the 9 in

Step-by-step explanation:

The volume of the gift box is 972 in. The height of the gift box is 12 inches

and the area of the base is 81 in².

We want to determine the length of each side of the square base if the base shape is a square.

Recall that, the area of a square is

{l}^{2}

It was given that, the area of this base is 81 in²

{l}^{2}  = 81

Take positive square root:

l =  \sqrt{81}  = 9in

5 0
3 years ago
Billie solved the equation below by completing the square, but she got the incorrect solution. In which step did Billie first ma
Tanzania [10]

Answer:

step 2

Step-by-step explanation:

we have

x^{2} +10x-49=0 ---> given problem

step 1

Move the constant to the right side

x^{2} +10x=49

the step 1 is correct

step 2

Complete the square

x^{2} +10x+5^2=49+5^2

x^{2} +10x+5^2=74

<u><em>The step 2 is not correct</em></u>

step 3

Rewrite as perfect squares

(x+5)^{2}=74

step 4

take square root both sides

x+5=\pm\sqrt{74}

step 5

Find the values of x

x=-5\pm\sqrt{74}

x=-5+\sqrt{74}

x=-5-\sqrt{74}

5 0
3 years ago
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