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mixas84 [53]
3 years ago
7

Whats the shaded region of 5/8​

Mathematics
2 answers:
exis [7]3 years ago
6 0
I believe the answer is H. hope this helps! try solving the rest and then use the remaining answer.
luda_lava [24]3 years ago
4 0

Answer:

  6.  5/8 = figure G

Step-by-step explanation:

In figure G, one full quarter and half of the other three quarters are shaded, so the total is ...

  1/4 + 1/2(3/4) = 2/8 +3/8 = 5/8

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A half-circle is joined to an equilateral triangle with side lengths of 12 units. What is the perimeter of the resulting shape?
krek1111 [17]

Answer:

P = 42.84  cm

Step-by-step explanation:

A half-circle is joined to an equilateral triangle with side lengths of 12 units.

We need to find the perimeter of the resulting shape.

The perimeter of the half cirle is πr.

The diameter of the circle is 12. It means radius is 6 units.

An equilateral triangle has 3 equal sides. So, perimeter of the triangle is given by :

P = πr  + 12 +12

= 3.14(6) + 24

= 42.84  cm

Hence, the perimeter of the resulting shape is 42.84  cm.

8 0
2 years ago
Help ASAP will give brainilist
Elenna [48]
It would be: 4 / 2/5

We can re-write it as:

4 * 5/2

= 20/2

= 10

In short, Your Answer would be: 10

Hope this helps!
5 0
3 years ago
Read 2 more answers
Distributive 8(4x+9)
Mariulka [41]

Answer: 32x + 72

Step-by-step explanation:

8*4x  +8*9

32x +72

3 0
3 years ago
What is f(5) if f(1) = 3.2 and f(x + 1) =5/2 (f(x))?
dimulka [17.4K]
F(x + 1) = (5/2)*f(x)

f(x + 1) = 2.5*f(x),           f(1) = 3.2

f(2) = 2.5f(1) = 2.5*3.2 = 8

<span>f(3) = 2.5f(2) = 2.5*8 = 20
</span>
f(4) = 2.5f(3) = 2.5*20 = 50

<span>f(5) = 2.5f(4) = 2.5*50 = 125</span>
8 0
3 years ago
Read 2 more answers
Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.
suter [353]

Answer:

\theta = 30^\circ, 330^\circ

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

Step-by-step explanation:

Given [Missing from the question]

Equation:

cos\theta = \frac{\sqrt 3}{2}

Interval:

0 \le \theta \le 360

0 \le \theta \le 2\pi

Required

Determine the values of \theta

The given expression:

cos\theta = \frac{\sqrt 3}{2}

... shows that the value of \theta is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

cos\theta = \frac{\sqrt 3}{2}

Take arccos of both sides

\theta = cos^{-1}(\frac{\sqrt 3}{2})

\theta = 30 --- In the first quadrant

In the fourth quadrant, the value is:

\theta = 360 -30

\theta = 330

So, the values of \theta in degrees are:

\theta = 30^\circ, 330^\circ

Convert to radians (Multiply both angles by \pi/180)

So, we have:

\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}

\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}

\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

8 0
2 years ago
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