Answer:
The center of that class, which is the sum of its largest and smallest values divided by 2 ⇒ E
Step-by-step explanation:
* Lets explain what is the class mid-point
- It is defined as the average of the upper and lower class limits
- The class midpoint is the lower class limit plus the upper class limit
divided by 2
- The easiest way to find the class mid-point is to add the upper
and lower boundary and divide your answer by two
- The lower limit for every class is the smallest value in that class.
- The upper limit for every class is the greatest value in that class
* <u><em>Lets solve the problem</em></u>
- It is not the largest value of that class minus the class width
- Its not the difference between the largest and smallest values of
that class
- It is not the difference between the largest and smallest values of
that class divided by 2
- It is the center of that class, which is the sum of its largest and
smallest values divided by 2
305.5 feet * .01 = 3.055 feet
Answer:
We make the table of these values at different values of x.
x A B C D
2 66.66 49.3 52.5 50
4 94.57 71.44 106.3 104
6 134.14 103.57 160.1 158
8 190.27 150.14 213.9 212
10 269.91 217.64 267.7 266
12 382.85 315.5 321.5 320.
Hence, the function that best represents the data is:
Option C.
y=26.9x-1.3
Step-by-step explanation:
Answer:
(0,-3) because its the coordinate
Answer:..
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Step-by-step explanation.:..
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