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3 years ago

Factor completely 4x^2+20x A: 4(x^2+5x) B: x(4x*20) C: 4x(x+5) D: prime

Mathematics

2 answers:

den301095 [7]3 years ago

5 0

C.

4x can go into both terms. So you left with 4x(x+5)

Vikentia [17]3 years ago

3 0

Answer:

4x(x+5)

Step-by-step explanation:

factor out the 4x out of the 4x^2

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Write seventy two thousand and thirty two ?

miv72 [106K]

In numbers, <span>seventy two thousand and thirty two is 72032</span>

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3 years ago

What is the expression (cscx+cotx)^2 the same as?

Nataly_w [17]

<span>c)1 + 2cot^2x + 2cscx cotx

because cosc^2x=1+cot^2x</span>

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3 years ago

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Write in simplest form:<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24a%5E%7B10%7Db%5E%7B6%7D%7D" id="TexFormula1" ti

Charra [1.4K]

Answer:

$2a^3b^2\sqrt[3]{3a}$

Step-by-step explanation:

Use the following rules for exponents:

$a^m*a^n=a^{m+n}\\\\\sqrt[3]{x^3}=x$

Simplify 24. Find two factors of 24, one of which should be a perfect cube:

$8*3=24\\\\2^3=8$

Insert:

$\sqrt[3]{2^3*3a^{10}b^6}$

Now split the exponents. Split 10 into as many 3's as possible:

$10=3+3+3+1$

Insert as exponents:

$\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^6}$

Split 6 into as many 3's as possible:

$6=3+3$

Insert as exponents:

$\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^3*b^3}$

Now simplify. Any terms with an exponent of 3 will be moved out of the radical (rule #2):

$2\sqrt[3]{3*a^3*a^3*a^3*a^1*b^3*b^3}\\\\\\2*a*a*a\sqrt[3]{3*a^1*b^3*b^3}\\\\\\2*a*a*a*b*b\sqrt[3]{3*a^1}$

Simplify:

$2a^3b^2\sqrt[3]{3a}$

:Done

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3 years ago

The quadratic function h(t)=-16.1t^2 + 150 models a balls height, in feet, over time, in seconds, after it is dropped from a 15

katrin [286]

<h2>Hello!</h2>

The answer is: The first graphic representation.

We are given a quadratic equation, meaning that it could be two possible solutions for the exercise, however, we are talking about time, so we have to consider only the obtained positive values.

Let's make the equation equal to 0 in order to find the values of "t"

$h(t)=-16.1t^2 + 150\\0=-16.1t^2 + 150\\16.1t^2=150\\t^2=\frac{150}{16.1}=9.32\\t=+-\sqrt{9.32}=+-3.05\\t1=3.05\\t2=-305$

So, discarding the negative value, we can use the possitive value to find the correct graphic representation.

To find the correct graphic representation we must take into consideration the following:

- We must remember that the sign of the coefficient of the quadratic term (t^2) will define if the parabola opens downward or upward.

From the given quadratic (or parabola) equation we have:

$a=-1\\b=0\\c=150$

So, since the coefficient of the quadratic term is negative, the parabola opens downward.

- Since we are looking for a graphic that represents the change in height over time, we need to look for a graphic that shows only positive values for the x-axis (time)

- We are looking for a parabola which y-axis intercept is equal to 150.

Therefore, the graphic representation of the quadratic function that models a ball's height over time is the first graphic representation.

Have a nice day!

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3 years ago

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Y_Kistochka [10]

Answer:

x ≈ 42.5

Step-by-step explanation:

We use tan∅ to solve this:

tanx° = 11/12

x° = $tan^{-1}(11/12)$

x = 42.5104°

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3 years ago