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Mandarinka [93]
3 years ago
6

Factor completely 4x^2+20x A: 4(x^2+5x) B: x(4x*20) C: 4x(x+5) D: prime

Mathematics
2 answers:
den301095 [7]3 years ago
5 0
C.

4x can go into both terms. So you left with 4x(x+5)
Vikentia [17]3 years ago
3 0

Answer:

4x(x+5)

Step-by-step explanation:

factor out the 4x out of the 4x^2

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Solve the following equation:<br> 9n² - n - 2/3 = 0
KIM [24]

Answer:

see explanation

Step-by-step explanation:

Given

9n² - n - \frac{2}{3} = 0 ← multiply through by 3 to clear the fraction

27n² - 3n - 2 = 0 ← factoring

Consider the factors of the product of the n² term and the constant term which sum to give the coefficient of the n- term

product = 27 × - 2 = - 54 and sum = - 3

The factors are - 9 and + 6

Use these factors to split the n- term

27n² - 9n + 6n - 2 = 0 ( factor the first/second and third/fourth terms )

9n(3n - 1) + 2(3n - 1) = 0 ← factor out (3n - 1) from each term

(3n - 1)(9n + 2) = 0

Equate each factor to zero and solve for n

3n - 1 = 0 ⇒ 3n = 1 ⇒ n = \frac{1}{3}

9n + 2 = 0 ⇒ 9n = - 2 ⇒ n = - \frac{2}{9}

3 0
3 years ago
What is the point of intercection of lines y=x and y=2x+1
12345 [234]

Answer:

(-1, -1)

Step-by-step explanation:

Let's set these two equations equal to each other to solve the system:

x = 2x + 1

Solving for x, we get x = -1

Plug this value of x back into any of the two equations to get y: y = 2 * (-1) + 1 = -1.

Thus, the point of intersection is (-1, -1).

Hope this helps!

8 0
3 years ago
Read 2 more answers
When 142 is added to a number, the result is 64 more times than 3 times the number. What is the number?
allsm [11]

x+142 =3x+64

subtract x from each side

142 = 2x+64

subtract 64 from each side

142-64 = 2x

78=2x

divide by 2

78/2 = x

x=39

The number is 39

3 0
3 years ago
Read 2 more answers
The length of a rectangle is 12 in and the perimeter is 56 what us the width of the rectangle
Aleks [24]
Hi there!

We can find the perimeter of a rectangle by using the following formula:

perimeter = 2 × width + 2 × length

In the question, we are given the following data: the length of the rectangle is 12 in and the perimeter is 56. Let's substitute this into our formula!

56 = 2 × width + 2 × 12
Multiply first.

56 = 2 × width + 24
Now subtract 24 from both sides.

32 = 2 × width
And finally, to find the width of the rectangle, divide both sides of the equation by 2.

16 = width
(we can eventually switch sides in the equation).

width = 16
~ Hope this helps you!
3 0
3 years ago
What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?
grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.  

1. Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.

Check:

  • 5\cdot 0=\overline{0};
  • 5\cdot 1=\overline{5};
  • 5\cdot 2=\overline{10};
  • 5\cdot 3=15=\overline{4};
  • 5\cdot 4=20=\overline{9};
  • 5\cdot 5=25=\overline{3};
  • 5\cdot 6=30=\overline{8};
  • 5\cdot 7=35=\overline{2};
  • 5\cdot 8=40=\overline{7};
  • 5\cdot 9=45=\overline{1};
  • 5\cdot 10=50=\overline{6}.

The multiplicative inverse of 5 in Z_{11} is 9.

2.   Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.

Check:

  • 5\cdot 0=\overline{0};
  • 5\cdot 1=\overline{5};
  • 5\cdot 2=\overline{10};
  • 5\cdot 3=15=\overline{3};
  • 5\cdot 4=20=\overline{8};
  • 5\cdot 5=25=\overline{1};
  • 5\cdot 6=30=\overline{6};
  • 5\cdot 7=35=\overline{11};
  • 5\cdot 8=40=\overline{4};
  • 5\cdot 9=45=\overline{9};
  • 5\cdot 10=50=\overline{2};
  • 5\cdot 11=55=\overline{7}.

The multiplicative inverse of 5 in Z_{12} is 5.

3.  Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.

Check:

  • 5\cdot 0=\overline{0};
  • 5\cdot 1=\overline{5};
  • 5\cdot 2=\overline{10};
  • 5\cdot 3=15=\overline{2};
  • 5\cdot 4=20=\overline{7};
  • 5\cdot 5=25=\overline{12};
  • 5\cdot 6=30=\overline{4};
  • 5\cdot 7=35=\overline{9};
  • 5\cdot 8=40=\overline{1};
  • 5\cdot 9=45=\overline{6};
  • 5\cdot 10=50=\overline{11};
  • 5\cdot 11=55=\overline{3};
  • 5\cdot 12=60=\overline{8}.

The multiplicative inverse of 5 in Z_{13} is 8.

8 0
3 years ago
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