Answer:
Show us the question
Step-by-step explanation:
L1: 2x+4y-3=0 ..........(1)
P: (2,0)
The point on the line L1 closest to the given point P is at the intersection of L1 with L2, which is the perpendicular passing through P.
Slope of L1=-2/4=-1/2
Slope of L2=-1/(-1/2)=2
Since it passes throug P(2,0), we can use the point-slope formula:
(y-0)=2(x-2) =>
L2: 2x-y-4=0.............(2)
Solve for x & y using (1) and (2) to get intersection point required:
(1)-(2)
2x-2x + 4y-(-y) -3 -(-4) =0
5y=-1, y=-1/5
Substitute y=1/5 in equation (1)
2x+4(-1/5)-3=0 =>
2x-19/5=0
x=19/10
=> the point on L1 closest to (2,0) is (19/10, -1/5)
(x•19)4=752
x would be multiplied by 19 then after it’s getting multiplied by 4.
Answer:
Q1
- cos 59° = x/16
- x = 16 cos 59°
- x = 8.24
Q2
BC is given 23 mi
<u>Maybe AB is needed</u>
- AB = √34² + 23² = 41 (rounded)
Q3
- BC² = AB² - AC²
- BC = √(37² - 12²) = 35
Q4
Let the angle is x
- cos x = 19/20
- x = arccos (19/20)
- x = 18.2° (rounded)
Q5
See attached
Added point D and segments AD and DC to help with calculation
- BC² = BD² + DC² = (AB + AD)² + DC²
<u>Find the length of added red segments</u>
- AD = AC cos 65° = 14 cos 65° = 5.9
- DC = AC sin 65° = 14 sin 65° = 12.7
<u>Now we can find the value of BC</u>
- BC² = (19 + 5.9)² + 12.7²
- BC = √781.3
- BC = 28.0 yd
<em>All calculations are rounded</em>
Answer:
Hopefully you dont get mad i answered for the points
Step-by-step explanation:
