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zalisa [80]
4 years ago
15

Which relationship exists between the two angles? What is the value of x? Find the measure of each angle. A) vertical angles; x

= 3; 76 degrees; 76 degrees B) alternate exterior angles; x = 5; 116 degrees; 64 degrees C) corresponding angles: x = 7; 156 degrees; 156 degrees D) alternate exterior angles; x = 5; 116 degrees; 116 degrees
Mathematics
2 answers:
Nutka1998 [239]4 years ago
7 0
The diagram shows angles (20x+16)° and (21x+11)° are alternate exterior angles, hence equal.
.. 20x +16 = 21x +11
.. 5 = x . . . . . . . . . . . . . subtract 20x +11
.. (20*5 +16)° = 116°

Selection D is appropriate.
ziro4ka [17]4 years ago
6 0
<span>D) alternate exterior angles; x = 5; 116 degrees; 116 degrees
</span>
If the diagram given by derricklawrence is correct, then you will realize that the angles with expressions are alternate exterior angles, so they have the same value, which means that the equations are equal to each other. So we can create the following equality:
21x + 11 = 20x + 16

Now to solve for x. Subtract 20x from both sides, getting:
x + 11 = 16

Subtract 11 from both sides, getting:
x = 5

Now substitute the known value for X into one of the equations.
20x + 16 = d
20*5 + 16 = d
100 + 16 = d
116 = d

And of the available options, choice "<span>D) alternate exterior angles; x = 5; 116 degrees; 116 degrees" is an exact match.

</span>
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The school that Joe goes to is selling tickets to a choral performance. On血e first day of ticket
ArbitrLikvidat [17]

Answer:

The price of one senior citizen ticket is $8, and the price of one child ticket is $11.

Step-by-step explanation:

You are looking for two things: the price of a senior citizen ticket and the price of a child ticket.

We need to write two equations using two variables.

Let s = price of 1 senior citizen ticket.

Let c = price of 1 child ticket.

First day of ticket sales:

6 senior citizen tickets, 8 child tickets, total sales of $136

Since s is the price of a senior citizen ticket, 6 tickets cost 6s.

Since c is the price of a child ticket, 8 tickets cost 8c.

The total sales is 6s + 8c.

The total sales is $136, so our first equation is

6s + 8c = 136

Now we do the same for the second day of ticket sales.

6 senior citizen tickets, 9 child tickets, total sales of $147.

Since s is the price of a senior citizen ticket, 6 tickets cost 6s.

Since c is the price of a child ticket, 9 tickets cost 9c.

The total sales is 6s + 9c.

The total sales is $147, so our second equation is

6s + 9c = 147

The system of equations is

6s + 8c = 136

6s + 9c = 147

Multiply both sides of the first equation by -1. Write the second equation below it. Then add the equations.

       -6s - 8c = -136

(+)     6s + 9c = 147

----------------------------

                  c =   11

c = 11, so the cost of a child ticket is $11.

Now substitute 11 for c in the first equation, and solve for s.

6s + 8c = 136

6s + 8(11) = 136

6s + 88 = 136

6s = 48

s = 8

The price of a senior citizen ticket is $8.

The price of a senior citizen ticket is $8, and the price of a child ticket is $11.

6 0
3 years ago
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