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Dennis_Churaev [7]
3 years ago
9

Can someone explain this

Mathematics
1 answer:
dolphi86 [110]3 years ago
6 0
<h3>Answer:   28</h3>

=========================================================

Explanation:

Let x be the unknown angle we want to find. This angle is in degrees.

The diagram shows 19 is the opposite of this angle, and the side 35 is adjacent to the angle.

We use the tangent ratio to tie the two sides together

\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(x) = \frac{19}{35}\\\\x = \tan^{-1}\left(\frac{19}{35}\right)\\\\x \approx 28.4956386\\\\x \approx 28\\\\

Note: The notation \tan^{-1} refers to the inverse tangent, or arctangent.

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What is the value of y in the equation 6 + y = −3? (1 point) Group of answer choices −3 −9 3 9
Paraphin [41]

Answer:

y= -9

Step-by-step explanation:

y+6=-3

subtract 6 from both sides

y=-9

4 0
2 years ago
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Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1
alexandr1967 [171]

Answer:

a) \simeq 0.3012   b) \simeq 0.0494 c) \simeq 0.2438

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, \frac{1.2}{4}

= 0.3 collisions per  month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

          P(X =x) = \frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}&#10;

                                                           for x ∈ N ∪ {0}

                       =  0 otherwise --------------------------------------(1)

here, \lambda = 0.3 collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

         P(X = 0) = \frac{e^{-0.3}\times {\0.3}^{0}}{0!}&#10;

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Now, since we are calculating  this for 4 months,

so, P(No collision in 4 month period)

     =0.7408182207^{4}

     \simeq 0.3012  -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

           P(X =1) = \frac{e^{-0.3}\times {\0.3}^{1}}{1!}&#10;

                      \simeq 0.2222454662 ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

                =0.2222454662^{2}

                \simeq 0.0494 -----------------------------------------(5)

1 collision in 6 months period means

                                \frac{1}{6} collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6]  (which is to be estimated)

=\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

\simeq 0.6543894283-------------------------------------------(6)

So,

P(1  collision in 6 month period)

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7 0
2 years ago
60 minutes is 20% of blank
leva [86]
60 = 0.20x
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6 0
3 years ago
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Shalnov [3]

Answer:

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3 0
2 years ago
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Sveta_85 [38]

Answer:

No

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Triangle ABC  54 +68 +  58 = 180

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In this case their corresponding angles are nor congruent

8 0
3 years ago
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