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2 years ago

14

How much money should be deposited today in an account that earns 4% compounded semi annually so that it will accumulate to 13,0

00 in 3 years?

1 answer:

DedPeter [7]2 years ago

5 0

Answer:

$11543.63

Step-by-step explanation:

<u>Plug information into A=P(1+r/n)^nt</u>

13000 = P(1+(.04/2))^(2*3)

13000 = P(1.02)^6

<u>Isolate P</u>

13000/(1.02^6) = P

P = $11543.63

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Let Y be a random variable with a density function given by

Neporo4naja [7]

From the given density function we find the distribution function,

$F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y$

(a)

$F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)$

$\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1$

$\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}$

(b)

$F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y$

$\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2$

$\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}$

(c)

$F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})$

$\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3$

$\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}$

5 0

3 years ago

Jarred sells DVDs. His inventory shows that he has a total of 3,500 DVDs. He has 2,342 more contemporary titles than classic tit

GaryK [48]

Answer: x = 2921, y = 579

Step-by-Step Explanation:

I am assuming that we just have to Solve for ‘x’ and ‘y’.

‘x’ = No. Of Contemporary Titles
‘y’ = No. Of Classic Titles

=> x + y = 3500 (Eq. 1)
=> x - y = 2342 (Eq. 2)

Adding Eq. 1 and Eq. 2, we get :-

2x = 3500 + 2342
2x = 5842
x = 5842/2
=> x = 2921

Therefore, x = 2921

Substitute value of ‘x’ in Eq. 1 :-

x + y = 3500
(2921) + y = 3500
y = 3500 - 2921
=> y = 579

Therefore, y = 579

Hence,
No. Of Contemporary Titles = 2921
No. Of Classic Titles = 579

6 0

2 years ago

I need this done asap

Norma-Jean [14]

Answer:

They both have 1/2

Step-by-step explanation:

For the first one there are 6 numbers and 3 of them are odd. That makes it 1/2.

For the second one it is self explanatory.

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2 years ago

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A football team has 26 players. How many more players should the coach recruit to meet his goal of having 32 players on the team

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3 years ago

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Draw and upload a box plot representing the following data set: 22, 35, 18, 30, 37, 20, 40, 18, 38, 38, 23, 19, 27, 31, 34.

marshall27 [118]

See the attached image for the box plot drawing. The five number summary is given below

Min = 18
Q1 = 20
Median = 30
Q3 = 37
Max = 40

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3 years ago

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