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3 years ago

51668 to the nearest hundred

Mathematics

1 answer:

julia-pushkina [17]3 years ago

7 0

Answer:

51700

Step-by-step explanation:

So basically you take the last three numbers. the middle 6 is over 5 so you round the first 6 to 7 and the rule for that is 5 or above round up 4 or below round down

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A number greater than a thousand whos prime factorization contains one prime number that does not repeat, one prime number that

Nikitich [7]

You can build as many numbers as you like: just pick three primes and repeat them as required.

The only caution is that you have to pick large enough primes to make sure that the result is larger than 1000.

Since $10^3 = 1000$ , it is enough that the prime repeating three times is larger than 10.

So, for example, we can pick

2, not repeating
3, repeating twice
11, repeating 3 times

The result is

$2 \times 3^2 \times 11^3 = 23958$

8 0

4 years ago

Which point would be a solution to the system of linear inequalities shown below? y>4 x-5\hspace{50px}y\ge\frac{3}{5} x-1 y&g

Sauron [17]

Answer:

$x < \frac{20}{17}$ and $y \ge \frac{-5}{17}$

Step-by-step explanation:

Given

$y>4 x-5\hspace{50px}y\ge\frac{3}{5} x-1$

Required

Find x and y

In the second equation. Assume that:

$y = \frac{3}{5}x - 1\\$

Substitute $y = \frac{3}{5}x - 1$ in the first equation

$y > 4x - 5$

$\frac{3}{5}x - 1 > 4x - 5$

Collect like terms

$\frac{3}{5}x - 4x > - 5 + 1$

$\frac{3}{5}x - 4x > -4$

Multiply through by 5

$3x - 20x > -20$

$-17x > -20$

Solve for x

$x < \frac{20}{17}$

Substitute this value of x in $y \ge \frac{3}{5}x - 1$

$y \ge \frac{3}{5}*\frac{20}{17} - 1$

$y \ge \frac{3}{1}*\frac{4}{17} - 1$

$y \ge \frac{12}{17} - 1$

$y \ge \frac{12- 17}{17}$

$y \ge \frac{-5}{17}$

3 0

3 years ago

Wat is the answer for this question -x2 + 5x + 24.

Helen [10]

Answer:

Step-by-step explanation:

5 0

3 years ago

Write the equation of the line that passes through the points (0,8) and (-1,-4).

Anettt [7]

Step-by-step:

Use slope formula to find the slope. (y - y)/(x - x)

Make sure the x and y in front of the minus is a pair that goes together, as well as the x and y behind the minus sign. So

8 - -4 goes on top, that's 12

0 - -1 goes under, thats 1

12/1 is the slope which is just 12. Use either point to fill in the second x and the second y in the point-slope equation. m is the slope.

y - y = m(x - x)

y - 8 = 12(x - 0)

y - 8 = 12x

5 0

3 years ago

A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1

Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find : transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0

3 years ago

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