Answer:
db / dt = kb
this becomes b(t) = Ce^(kt)
C = 100, the initial population
P(1) = 420 = 100 e^(1k)
4.2 = e^k
ln 4.2 = k
a) thus, b(t) = 100 e^(t ln 4.2)
b) b(3) = 100 e^(3 ln 4.2)
c) growth constant will still be ln 4.2 (constant percentage of populatioin)
d) 10000 = 100 e^(t ln 4.2)
100 = e^(t ln 4.2)
ln 100 = t ln 4.2
t = ln 100 / ln 4.2
Step-by-step explanation:
The value of x in terms of p is 15/p.
The value of x when p is -5 is -3.
Pls tell me if i’m wrong in any way!
Answer:
The answer is c = 2 + 3d .
Step-by-step explanation:
It is given that a cab ride cost $2 which is a fixed amount and charges additional $3 per mile. So you have to make an equation of c in terms of d :
Let c be the cost,
Let d be the distance,
c = 2 + 3d
Step-by-step explanation:
512+18=530
423+12=435
5421+14=5435
6324+32=6356
7985+23=8008
