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Rashid [163]
3 years ago
15

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Mathematics
1 answer:
RoseWind [281]3 years ago
7 0
Be quiet! Be quiet!

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20. What is the value of y in the algebraic
Dennis_Churaev [7]

Answer: 17/7

Step-by-step explanation: Step 1: Simplify both sides of the equation. y+4/15 + 2y−5/5 = 2/5 1/15 y+ 4/15 + 2/5 y+−1= 2/5 (Distribute) ( 1/15 y+ 2/5 y)+( 4/15 +−1)= 2/5 (Combine Like Terms) 7/15 y+ −11/15 = 2/5 7/15 y+ −11/15 = 2/5 Step 2: Add 11/15 to both sides. 7/15 y+ −11/15 + 11/15 = 2/5 + 11/15 7 15 y= 17/15

7 0
3 years ago
There are 3 red marbles, 5 green marbles, and 2 blue marbles in a jar. Event A is defined as drawing a red marble from the jar o
Anastaziya [24]

P(B/A) is \frac{5}{9} in the simplest form

Step-by-step explanation:

Let us explain how to solve the problem

  • P(B|A) is called the "Conditional Probability" of B given A
  • Conditional probability is the probability of one event occurring with some relationship to one or more other events that means event A has already happened, now what is the chance of event B
  • The formula for conditional probability is P(B|A) = P(A and B)/P(A), where P(A and B) is P(A) . P(B given A occurred)

∵ There are 3 red marbles, 5 green marbles, and 2 blue

   marbles in the jar

∴ The total number of the marbles in the jar = 3 + 5 + 2 = 10

∵ Two marbles are drawn from the bag, one after the other without

   replacement

- That means red is already occurred when green is happened,

  so it is a "Conditional Probability" of green given red

  P(B/A) = P(A and B)/P(A)

∵ Event A is defined as drawing a red marble from the jar on

   the first draw

∴ P(A) = P(red)

∵ P(red) = \frac{3}{10}

∴ P(A) = \frac{3}{10}

∵ Event B is defined as drawing a green marble on the second draw

∴ P(B) = P(green)

- The number of marbles after the red is chosen is 9

∵ P(green) = \frac{5}{9}

∴ P(B) = \frac{5}{9}

- Find P( A and B)

∴ P(A and B) = ( \frac{3}{10} ) . ( \frac{5}{9} )

∴ P(A and B) = \frac{15}{90}

- Simplify the fraction by divide up and down by 15

∴ P(A and B) = \frac{1}{6}

∵ P(B|A) = P(A and B)/P(A)

- Substitute the values of P(A and B) and P(A) in the rule above

∴ P(B/A) = \frac{\frac{1}{6}}{\frac{3}{10}}

- Simplify the fraction

∵ \frac{1}{6} ÷ \frac{3}{10} = \frac{1}{6} × \frac{10}{3} = \frac{10}{18}

- Divide up and down by 2

∴ P(B/A) = \frac{5}{9}

P(B/A) is \frac{5}{9} in the simplest form

Learn more:

You can learn more about probability in brainly.com/question/10744457

#LearnwithBrainly

7 0
3 years ago
Read 2 more answers
A bag contains 15 counters:7 red 4 blue and 4 green.a counter is taken out of the bag at random.what is the probability of choos
Nikitich [7]

|\Omega|=15\\|A|=7+4=11\\\\P(A)=\dfrac{11}{15}\approx73.3\%

3 0
2 years ago
Read 2 more answers
Thirty adults were asked how many pets they have had over their lifetime.
madam [21]
The statement that is most likely true is that the median is in the 6-10 interval and the mean is in the 6-10

There were a total of 30 different pieces of data collected, so the 15th and 16th pieces of data that would create the median. Both the 15th and 16th numbers would be in the 6 - 10.

If you find the average of the middle data point in each interval the mean would be approximately 7.2. This is in the 2nd interval (6-10).



4 0
3 years ago
Read 2 more answers
Polly bought a cracker for $3 and then bought a parrot for $4. By how much did Polly's account change after her transactions?
nikitadnepr [17]

Answer: -7$ or down by 7$

Step-by-step explanation: Her account went down by 7 or x - 7.

Hope this helped!

Mark Brainliest if you want!

8 0
3 years ago
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