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Masja [62]
3 years ago
8

What is the midpoint of the line segment with endpoints (-1,7) and (3, -3)?

Mathematics
1 answer:
Elodia [21]3 years ago
4 0
The correct answer is A. (1, 2)
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Stuck, anyone can help?
expeople1 [14]

Answer:

Step-by-step explanation:

\sqrt{x-3} = x - 5 ( x ≥ 3 )

( \sqrt{x-3} )² = ( x - 5 )²

x - 3 = x² - 10x + 25

x² - 11x + 28 = 0

(x - 4)(x - 7) = 0

x_{1} = 7

x_{2} = 4

Check the answer:

1). x = 7

\sqrt{7-3} = 7 - 2

√4 = 2

2 = 2

2). x = 4

\sqrt{4-3} = 4 - 5

1 = - 1 (False statement) ⇒ x = 4 is an extraneous solution.

6 0
3 years ago
A given line has the equation 10x + 2y = −2.
stepladder [879]
10x + 2y = -2

2y = -10x -2

y = -5x - 1 (slope is -5 and a parallel line will have the same slope)


y = mx + b

slope(m) = -5

12 = -5(0) + b

12 = 0 + b

12 = b

so the parallel line is y = -5x + 12

hope this helps, God bless!

3 0
3 years ago
Review
miv72 [106K]

Step-by-step explanation:

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4 0
3 years ago
Select the correct answer from each drop-down menu.
Aleksandr [31]

Answer:

b

Step-by-step explanation:

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3 years ago
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