Answer:
Here is the process I did:
2(6x+4)-6+2x=3(4x+3)+1
Step 1: Distribute the 2 to the numbers in the parentheses (6x +4) on the left side of the equation
6x(2)+4(2)-6+2x=3(4x+3)+1
12x+8-6+2x=3(4x+3)+1
Step 2: On the left side of the equation combine like terms
x's go with x's (12x and 2x):
(12x + 2x)+8-6=3(4x+3)+1
14x+8-6=3(4x+3)+1
normal numbers go with normal numbers ( 8 and -6):
14x+(8+(-6))=3(4x+3)+1
14x+2=3(4x+3)+1
Step 3: Distribute the 3 to the numbers in the parentheses (4x+3) on the right side of the equation
14x+2=4x(3) +3(3) + 1
14x+2=12x + 9 + 1
Step 4: On the right side of the equation combine like terms
normal numbers go with normal numbers ( 9 and 1):
14x+2=12x + (9 + 1)
14x+2=12x + 10
Step 5: Bring 2 from the left side to the right by subtracting it to both sides
14x+(2-2)=12x + (10-2)
14x = 12x + 8
Step 6: Bring 12x from the right side to the left by subtracting it to both sides
(14x - 12x) = (12x - 12x) + 8
2x = 8
Step 7: Isolate x by dividing 2 to both sides
x = 4
Hope this helped!
Answer:
31. 122
32. 2400 cans
Step-by-step explanation:
31.
fig 1=1
fig 2=10
fig 3=26
fig 4=50
fig 5=82
fig 6=122
32. 520/13=40
40(60)=2400
1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP
If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8
2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2
Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4
FC= 2/(1+2) * AC
FC= 2/3 * 12= 8
3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
-2x=4
x=-2
DC=3x+12= 3(-2) +12= 6
4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3
C
BC lines slope would be (-1)-(-1)/4 = 0/4.
The line would be
0=x+a
a=-1
0=x-1
x=1
y=-x-1 = 1/3x-7/3
-x-(1/3x)=-7/3 +1
-4/3x= -4/3
x=1
y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)
5.
a. Circumcenter: the intersection of perpendicular bisector lines<span>
b. Incenter: the intersection of bisector lines
c. Centroid: </span>the intersection of median lines<span>
d. Orthocenter: </span>the intersection of altitude lines
Answer:
2:50 PM
Step-by-step explanation:
Step 1: State what is given
Roast takes 3 hours and 40 minutes or 220 minutes
Need the roast to be done by 6:30 PM
Step 2: Subtract 3 hours from 6:30
6:30 - 3:00
3:30 PM
Step 3: Subtract 40 minutes from 3:30
3:30 - 40
2:50 PM
Therefore the roast needs to be put into the oven at 2:50 PM
