3 divided by the sum of x and 9

Mathematics

1 answer:

Leto [7]2 years ago

5 0

Answer:3/9

Step-by-step explanation:

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7x^2=9+x what are the values of x Will give medal and points

DENIUS [597]

7x² = 9 + x Subtract x from both sides
7x² - x = 9 Subtract 9 from both sides
7x² - x - 9 = 0 Use the Quadratic Formula

a = 7 , b = -1 , c = -9

x = $\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ Plug in the a, b, and c values
x = $\frac{- (-1) \pm \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}$ Cancel out the double negative
x = $\frac{1 \pm \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}$ Square -1
x = $\frac{1 \pm \sqrt{1 - 4(7)(-9)} }{2(7)}$ Multiply 7 and -9
x = $\frac{1 \pm \sqrt{1 - 4(-63} }{2(7)}$ Multiply -4 and -63
x = $\frac{1 \pm \sqrt{1 + 252} }{2(7)}$ Multiply 2 and 7
x = $\frac{1 \pm \sqrt{1 + 252} }{14}$ Add 1 and 252
x = $\frac{1 \pm \sqrt{253} }{14}$ Split up the $\pm$
x = $\left \{ {{ \frac{1 + \sqrt{253} }{14} } \atop { \frac{1 - \sqrt{253} }{14} }} \right.$
The approximate square root of 253 is 15.905973.
x ≈ $\left \{ { \frac{1 + 15.905973}{14} } \atop { \frac{1 - 15.905973}{14} }} \right$ Add and subtract
x ≈ $\left \{ {{ \frac{16.905973}{14} } \atop { \frac{14.905973}{14} }} \right.$ Divide
x ≈ $\left \{ {{1.2075} \atop {1.0647}} \right.$ Round to the nearest hundredth
x ≈ $\left \{ {{1.21} \atop {1.06}} \right.$

7 0

3 years ago

A poster is shown below: A rectangle is shown. The length of the rectangle is labeled 12 feet. The width of the rectangle is lab

klemol [59]

It would be 7.5ft by 30ft
Because I just multiplied 12 by 5/2 which is 30
Then I multiplied 3 by 5/2 which is 7.5

6 0

3 years ago

Read 2 more answers

Explain the steps you would take to complete this conversion problem

OLEGan [10]

Answer:

20909.09 grams

Step-by-step explanation:

$\frac{46 \: lb}{1} \times \frac{1 \: kg}{2.2 \: lb} \times \frac{1000 \: g}{1 \: kg} = \\ \frac{46 \: lb}{2.2 \: lb} \times \frac{1 \: kg}{1} \: \times \frac{1000 \: g}{1 \: kg} = \\\frac{230 \: }{11 \:} \times \frac{1 \: kg}{1 \: kg \:}\times \frac{1000 \: g}{1 \:} = \\\frac{230 \: }{11 \:} \times \frac{1}{1}\times \frac{1000 \: g}{1 \:} = \\\ \frac{230}{11}g \times 1g \times \: 1000g$