Question

The function f(t) = 1100(0.9945)^t represents the change in a quantity over t weeks. What does the constant 0.9945 reveal about the rate of change of the quantity

Answer 1

Answer:

As t increases, the quantity reduces

Step-by-step explanation:

Given

$f(t) = 1100(0.9945)^t$

Required

What does the rate (0.9945) reveal about the function

From the given function, the rate b is:

$b = 0.9945$

When b has the following range:

$0$

Then, it means there is a reduction

In other words, as the number of weeks (t) increases, the quantity (f(t)) reduces