Miu will solve the system of equations below using the elimination method.

If the diffrence in the side lenghts of two squares is 10,and the sum of the side lenghts is 18, what are the side lengths

konstantin123 [22]

Answer:

The side of first square =14 units

side of second square =4 units

Step-by-step explanation:

We have given two squares,

A square have all its four sides equal and at right angles.

Let the side of first square be 'a'

and the side of second square be 'b'

Given:

$a-b=10$ equation:1

$a+b=18$ equation:2

Solving equation:1

a=10+b equation:3

Putting 'a' in equation:2

$(10+b)+b=18\\\\2b=18-10\\\\2b=8\\\\b=4$

Putting 'b' in equation:3

$a=10+4\\\\a=14$

So, the side of first square is 14 units and

side of second square is 4 units

5 0

2 years ago

The graph shown represents Tommy’s drive to work as a function of his distance from home over time:

8_murik_8 [283]

I am trying to figure it out

3 0

3 years ago

Read 2 more answers

It seems to you that fewer than half of people who are registered voters in the City of Madison do in fact vote when there is an

Ad libitum [116K]

Answer:

a) Going to public places like restaurants, parks, theaters, etc in Madison and asking voters.

b) The 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections is (0.5533, 0.6667).

c) We are 80% sure that our confidence interval contains the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

d) The lower limit of the interval is higher than 0.5. This means that it does seem that MORE than half of registered voters in the City of Madison vote in non-presidential elections.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

(a) How might a simple random sample have been gathered?

Going to public places like restaurants, parks, theaters, etc in Madison and asking voters.

(b) Construct an 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

You take an SRS of 200 registered voters in the City of Madison, and discover that 122 of them voted in the last non-presidential election. This means that $n = 200, \pi = \frac{122}{200} = 0.61$ .

We want to build an 80% CI, so $\alpha = 0.20$ , z is the value of Z that has a pvalue of $1 - \frac{0.20}{2} = 0.90[tex], so [tex]z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{200}} = 0.61 - 1.645\sqrt{\frac{0.61*0.39}{200}} = 0.5533$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{200}} = 0.61 + 1.645\sqrt{\frac{0.61*0.39}{200}} = 0.6667$

The 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections is (0.5533, 0.6667).

(c) Interpret the interval you created in part (b).

We are 80% sure that our confidence interval contains the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

(d) Based on your CI, does it seem that fewer than half of registered voters in the City of Madison vote in non-presidential elections? Explain.

The lower limit of the interval is higher than 0.5. This means that it does seem that MORE than half of registered voters in the City of Madison vote in non-presidential elections.

4 0

2 years ago

Eric's cell phone service costs $40.00 a month for unlimited calls. He also pays $0.02 for each text message he sends.

Kaylis [27]

Answer:

A. 40.021

Step-by-step explanation:

Unlimited calls = $40

Text message = $0.021

NOTE:There is a difference between the value you gave for cost of text messages in the question and the values given in the group of answers. I will use $0.021 for cost of text messages since it is common to all answer choices.

Total cost = Cost of unlimited calls + cost of text messages

C = $40 + $0.021

= $40.021

Therefore, the equation which represent the total cost in dollars for a month is 40.021

A. 40.021

4 0

2 years ago

Which system of linear inequalities Is represented by this graphed solution?

SashulF [63]

Answer:

y ≥ 3x - 1

y < $-\frac{1}{2}x+2$

Step-by-step explanation:

Let the equation of the solid line passing through (x', y') given in graph is,

y = mx + b

Here m = slope of the line

b = y-intercept

Slope of the solid line =

m = $\frac{3}{1}$

m = 3

y - intercept 'b' = -1

Therefore, equation of the line will be,

y = 3x - 1

Since, shaded (blue) area is above the line, inequality that will represent the solution area will be,

y ≥ 3x - 1

For the dotted line,

Slope of the line (m) = $\frac{\text{Rise}}{\text{Run}}$

= $\frac{-2}{4}$

= $-\frac{1}{2}$

y-intercept (b) = 2

Equation of the dotted line → y = $-\frac{1}{2}x+2$

Since, shaded (grey color) area is below the dotted line,

Inequality representing the solution area will be,

y < $-\frac{1}{2}x+2$

7 0

2 years ago