Answer:
The correct answer is option (C)-0.245 = 2.160(0.205)
Step-by-step explanation:
Solution
Given that:
The slope = - 0.245
The size sample = n = 15
The standard error = 0.205
The confidence level = 95
The Significance level= α = (100- 95)% = 0.05
Now,
The freedom of degree = n-2 = 15 -2= 13
Thus,
the critical value = t* = 2.16
By applying Excel = [TINV (0.05, 13)]
The Margin of error is = t* (standard error)
=2.16 *0.205
= 0.4428
Answer: 6.25 miles
Step-by-step explanation:
Convert the 15 minutes to 1/4 hr or .25
now multiply 25*.25=6.25 miles
Answer:
Step-by-step explanation:
There are three reasons here why randomization is not being applied.
First, the coach is only observing football players attending the meeting. This is not representative of the entire team.
Second, there is no selection process. The coach isn't using a random generator or using a similar method.
Third, the players are volunteering for the test. The results will be biased because of this.
Okay so for number 3, you have to do the top work first.
3: POSITIVE 2!! first, you do the stuff inside the parentheses first because of P(parentheses)EMDAS. so, 14-2-10! -2-10 is -12 and then plus positive 14 is +2. but, the negative sign outside of the parentheses makes that +2 a -2.
but, you cant forget the -12 outside. you have to do -12-2 which gets you -14. then, this is easy! -14 divided by -7 is a positive 2!
5: POSITIVE 3!! again, do the stuff in the parentheses first!! -2-4 is -6. then, -6 x 2 is -12! so, divide -12 by -4 and you get a positive 3!
28=2*2*7=2²*7;
46=2*23=>the greatest common factor is 2
