To determine the height of the object after a certain time it is dropped, we simply substitute the time to the function given. We calculate as follows:
h = -16t^2 + 1454
h = -16(8^2) + 1454
h = 430 feet above the ground
Hope this answers the question. Have a nice day.
Number Two:
The formula to find the volume of a triangular prism is the area of the triangle/base multiplied by the height.
Finding the area of the base:
10×15=150×0.5=75
Now multiply it by its height.
75×25
1,875 m³
Number Four:
You need to multiply the width times the height times the length, or in any arrangements. Everything needs to get mutiplied together.
1×2.5
2.5×9
22.5 cm³
Answer:

And when we apply the limit we got that:

Step-by-step explanation:
Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"
We have the following formula in order to find the sum of cubes:

We can express this formula like this:
![\lim_{n\to\infty} \sum_{n=1}^{\infty}i^3 =\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2](https://tex.z-dn.net/?f=%20%5Clim_%7Bn%5Cto%5Cinfty%7D%20%5Csum_%7Bn%3D1%7D%5E%7B%5Cinfty%7Di%5E3%20%3D%5Clim_%7Bn%5Cto%5Cinfty%7D%20%5B%5Cfrac%7Bn%28n%2B1%29%7D%7B2%7D%5D%5E2)
And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2
![\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2](https://tex.z-dn.net/?f=%20%5Clim_%7Bn%5Cto%5Cinfty%7D%20%5B%5Cfrac%7Bn%28n%2B1%29%7D%7B2%7D%5D%5E2)
If we operate and we take out the 1/4 as a factor we got this:

We can cancel
and we got

We can reorder the terms like this:

We can do some algebra and we got:

We can solve the square and we got:

And when we apply the limit we got that:

Answer:
Domain: 1, 6
Range: 4
Step-by-step explanation:
The Domain is the first coordinate which is x
The Range is the second coordinate which is y