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zepelin [54]
3 years ago
10

4) Solve Ax + By = C, for y

Mathematics
2 answers:
irina1246 [14]3 years ago
4 0

Answer:Ax + By = C

-ax -ax

-------------------

By = -Ax + C

--- ------------

B B

--------------------

y = -Ax + C

----------

B

Step-by-step explanation:

raketka [301]3 years ago
3 0

Answer:

y=c/b-ax/b

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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The height, h, in feet, of an object dropped from the top of the Empire State Building can be estimated using the equation h= -1
Ksju [112]
To determine the height of the object after a certain time it is dropped, we simply substitute the time to the function given. We calculate as follows:

h = -16t^2 + 1454
h = -16(8^2) + 1454
h = 430 feet above the ground

Hope this answers the question. Have a nice day.
7 0
3 years ago
Can someone please help me: fine the volume btw for #2
ICE Princess25 [194]
Number Two:
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10×15=150×0.5=75
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Number Four:
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8 0
4 years ago
Read 2 more answers
The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit in
Marina86 [1]

Answer:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

Step-by-step explanation:

Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"

We have the following formula in order to find the sum of cubes:

\lim_{n\to\infty} \sum_{n=1}^{\infty} i^3

We can express this formula like this:

\lim_{n\to\infty} \sum_{n=1}^{\infty}i^3 =\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2

And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2

\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2

If we operate and we take out the 1/4 as a factor we got this:

\lim_{n\to\infty} \frac{n^2(n+1)^2}{n^4}

We can cancel n^2 and we got

\lim_{n\to\infty} \frac{(n+1)^2}{n^2}

We can reorder the terms like this:

\lim_{n\to\infty} (\frac{n+1}{n})^2

We can do some algebra and we got:

\lim_{n\to\infty} (1+\frac{1}{n})^2

We can solve the square and we got:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

3 0
3 years ago
Find the domain & range, pls helpp
shutvik [7]

Answer:

Domain: 1, 6

Range: 4

Step-by-step explanation:

The Domain is the first coordinate which is x

The Range is the second coordinate which is y

5 0
3 years ago
Read 2 more answers
Solve for x <br><br> 2x-20=450
Pachacha [2.7K]

2x-20=450

2x=450+20

2x/2=470/2

x=235

6 0
3 years ago
Read 2 more answers
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