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notka56 [123]
3 years ago
8

Solve each system by elimination. 1) –3x – 6y= -3 5x + 5y=0

Mathematics
2 answers:
sveticcg [70]3 years ago
7 0

Answer: x=−1 and y=1.

Step-by-step explanation: −3x−6y=−3;5x+5y=0

5(−3x−6y=−3)

6(5x+5y=0)

−15x−30y=−15

30x+30y=0

15x /15 = −15 /15

x=−1

−3x−6y=−3

(−3)(−1)−6y=−3

−6y+3+−3=−3+−3

−6y /−6 = −6 /−6

y=1

x=−1 and y=1

dexar [7]3 years ago
6 0

Answer: look at the picture

Step-by-step explanation: Hope this help :D

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(15x^2 -35x +10)÷5

15/5 x^2 -35/5 x +10/5

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A candy company can make 350 pounds of chocolate and 6 hours how much can they make in 10 hours
Andrew [12]

350 ÷ 6 = 58.33

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In the diagram below <br> Please help I’ll give brainliest
Luda [366]

Answer:

m<GFA = 110

Step-by-step explanation:

1. ABCD - parallelogram                          Definition of a parallelogram

                                                                   (AB ll CD) (AD ll BC)

2. m<B + m<C = 180                                    Consectuive angles in a

   110 + m<C = 180                                       parallelogram are supplementary

    m<C = 70                                    

3. m<GCB = 1/2 m<C                                  Definition of angles bisector

   m<GCB = 70

4. m<B = m<D = 110                                    Opposite angles in a

                                                                    parrallelogram are congruent

5. m<CDG = 1/2 m<D                                 Defintion of an angle bisector

  m<CDG = 55

6. m<GCB+m<CDG+m<CGD=180              Sum of anlges in a triangle (ΔCDG)

  70 + 55 + m<CGD = 180

   125 + m<CGD = 180

   m<CGD = 55

7. m<CGD + m<DGF = 180                            Linear pair, supplmentary angles

  55 + m<DGF = 180

  m<DGF = 125

8. m<C = m<A = 70                                     Opposite angles in a paralellogram

                                                                     are congruent

9. m<ADG = 1/2m<D                                       Definiton of an angle bisector

  m<ADG = 55

10.m<ADG+m<DFG+m<GFA+m<A=360        Sum of angles in quadrilateral

   55 + 125 + m<GFA + 70 = 360                    DGFA

    m<GFA + 250 = 360

   m<GFA = 110

4 0
3 years ago
Solve fro the Equation below:<br><br> 7+2(x-3)=-3(x+1)-4
tester [92]
7 + 2x - 6 = -3x - 3 - 4
2x + 1 = -3x - 3 - 4
2x + 1 = -3x - 7
2x + 1 + 3x = -7
5x + 1 = -7
5x = -7 - 1
5x = -8
x = -8/5.
4 0
3 years ago
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