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Aleksandr-060686 [28]

3 years ago

5

Find the slope of the following equation y=-6/7x+42? I'm so stuck can someone help?

1 answer:

umka21 [38]3 years ago

8 0

Answer:

Step-by-step explanation:

the slope is in the equation

-6/7 is the slope

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What is the median of this set of measurements? 10cm, 15cm, 15cm, 18cm, 20cm.

Alinara [238K]

Answer:

15 cm

Step-by-step explanation:

Median means middle number

10,15,15,18,20

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3 years ago

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Can someone help me with this problem

riadik2000 [5.3K]

Answer:

d=16t squared

Step-by-step explanation:

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3 years ago

Find the complete factored form of the polynomial -24a6b4-40a3

Naddik [55]

For this case we have the following polynomial:

$-24a ^ 6b ^ 4-40a ^ 3$

We must find the greatest common factor of the terms of the polynomial.

The GCF of the coefficients is given by:

$24 = 3 * 8\\40 = 5 * 8$

Then we look for the GFC of the variables:

We have then:

$a ^ 6 = a ^ 3a ^ 3\\a ^ 3 = a ^ 3$

Finally rewriting we have: $-24a ^ 6b ^ 4-40a ^ 3 = -8a ^ 3 (3a ^ 3b ^ 4 + 5)$

Answer:

the complete factored form of the polynomial is:

$-8a ^ 3 (3a ^ 3b ^ 4 + 5)$

8 0

3 years ago

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

3 years ago

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Which is the correct use of the distributive property?

sergiy2304 [10]

Answer:

42+18=6(7+3)

Step-by-step explanation:

6x7=42 and 6x3=18

4 0

3 years ago

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