Answer:
The correct option is O B'
Step-by-step explanation:
We have a quadrilateral with vertices A, B, C and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units away from the line, C is 7 units away from the line and D is 9 units away from the line.
Now we perform the reflection and we obtain a new quadrilateral A'B'C'D'.
In order to apply the reflection to the original quadrilateral ABCD, we perform the reflection to all of its points, particularly to its vertices.
Wherever we have a point X and a line of reflection L and we perform the reflection, the new point X' will keep its original distance from the line of reflection (this is an important concept in order to understand the exercise).
I will attach a drawing with an example.
Finally, we only have to look at the vertices and its original distances to answer the question.
The vertice that is closest to the line of reflection is B (the distance is 4 units). We answer O B'
Answer:
1530
Step-by-step explanation:
We already know that 5 hours is 510 miles and to know how much is 15 hours you will add 510 3 times 510 + 510 + 510 what 1530 would give
Answer:
D. 2,5, and 6
Step-by-step explanation:
Because if u mutiply 2*5 = 10 and 2*6 is 12 as 5*6 is 30 and 2*9 is 18 .
Answer:
259.6 ft/sec
Step-by-step explanation:
it is a universal standard that acceleration due to gravity is 32ft/sec^2.
Now it can be verified by equation,
V(f) = V(i)+at (1st equation of motion derived by Newton's three laws of motion)
where,
V(f) is final velocity
V(i) is initial velocity
a is acceleration which is constant and have value 32ft/sec^2
t is time which is given as 7.8 seconds
In the given case, initial velocity that is V(i) will be 0ft/sec. Because, on dropping, object will start to move under the influence of gravity from zero speed.
So,
V(f) = 0 +(32) (7.8)
V(f) = 249.6 ft/sec
Now the condition is given that you have to add a constant 10 to the answer.
so, V(f) = 249.6 + 10
V(f) = 259.6 ft/sec
Answer:
The correct option is;
10 m
Step-by-step explanation:
The parameters given are;
Height of the first pole = 20 m
Height of the second pole = 14 m
The angle the wire connected to their top makes with the horizontal = 30°
The vertical height subtended by the inclined wire, h = The difference in height between the two poles = 20 - 14 = 6 m.
Let the horizontal distance between the two poles = D
Therefore;
The horizontal length of the wire = D
From trigonometric ratios, we have;
Which gives;
The correct option is 10 m.
