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garik1379 [7]
2 years ago
14

Which of the following statements are true?

Mathematics
1 answer:
kow [346]2 years ago
7 0

The true statements are; A. Both graphs have exactly one asymptote. C. Both graphs are exponential functions. B. Both graphs have been shifted and flipped.

<h3>What are exponential functions?</h3>

When the expression of function is such that it involves the input to be present as an exponent (power) of some constant, then such function is called exponential function.

There usual form is specified below. They are written in several such equivalent forms.

For example, y^x

, where a is a constant is an exponential function.

The graphs are exponential functions because as x increases, the y approaches infinity.

Here, the graphs have exactly one asymptote.

we can see that both graphs appear to have been shifted and flipped especially when at their respective coordinates.

The true statements are;

A. Both graphs have exactly one asymptote.

C. Both graphs are exponential functions.

B. Both graphs have been shifted and flipped.

Read more about Function Graphs at;

brainly.com/question/11507546

#SPJ1

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Whats the answer??? Pleaseeee!!!!
kvasek [131]

To find the 20th term in this sequence, we can simply keep on adding the common difference all the way until we get up to the 20th term.

The common difference is the number that we are adding or subtracting to reach the next term in the sequence.

Notice that the difference between 15 and 12 is 3.

In other words, 12 + 3 = 15.

That 3 that we are adding is our common difference.

So we know that our first term is 12.

Now we can continue the sequence.

12 ⇒ <em>1st term</em>

15 ⇒ <em>2nd term</em>

18 ⇒ <em>3rd term</em>

21 ⇒ <em>4th term</em>

24 ⇒ <em>5th term</em>

27 ⇒ <em>6th term</em>

30 ⇒ <em>7th term</em>

33 ⇒ <em>8th term</em>

36 ⇒ <em>9th term</em>

39 ⇒ <em>10th term</em>

42 ⇒ <em>11th term</em>

45 ⇒ <em>12th term</em>

48 ⇒ <em>13th term</em>

51 ⇒ <em>14th term</em>

54 ⇒ <em>15th term</em>

57 ⇒ <em>16th term</em>

60 ⇒ <em>17th term</em>

63 ⇒ <em>18th term</em>

66 ⇒ <em>19th term</em>

<u>69 ⇒ </u><u><em>20th term</em></u>

<u><em></em></u>

This means that the 20th term of this arithemtic sequence is 69.

5 0
3 years ago
PLEASE HELP!!!!! Write the absolute value inequality in the form
Elena-2011 [213]

Answer:

|x - 1 |> 6,

Step-by-step explanation:

First we find the distance between the two points

-5 to 7

7 - -5 =7+5 = 12

We find 1/2 that distance

12/2 = 6

So we are looking for a greater-than inequality  because we are looking for the outsides because we want a less than and a greater than

|x - b |> c,

The center is 6 to that is c

|x - b |> 6,

To find the value of b

Let x = 7

7 -b =6

b=1

|x - 1 |> 6,

We can check by using -5

|-5 - 1 |> 6,

7 0
3 years ago
Read 2 more answers
Find the shortest distance from point A to the given line.
podryga [215]

Step-by-step explanation:

please i work on by paper worksheet, see it

how can i work it

4 0
3 years ago
A set of data items is normally distributed with a mean of 400 and a standard deviation of 60. Find the data item in this distri
Softa [21]

Answer:

The data item is X = 580

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 400 and a standard deviation of 60.

This means that \mu = 400, \sigma = 60

z=3

We have to find X when Z = 3. So

Z = \frac{X - \mu}{\sigma}

3 = \frac{X - 400}{60}

X - 400 = 3*60

X = 580

The data item is X = 580

6 0
3 years ago
Suppose $p(x)$ is a monic cubic polynomial with real coefficients such that $p(3-2i)=0$ and $p(0)=-52$. determine $p(x)$ (in exp
Maslowich

If p(3-2i)=0, then complex number 3-2i is a root of cubic polynomial.

If polynomial has real coefficients, then conjugated 3+2i is also a root of polynomial.

Then the polynomial will be of a form

p(x)=(x-(3-2i))(x-(3+2i))(x-a).

Since p(0)=-52, then

-52=(0-(3-2i))(0-(3+2i))(0-a),\\ \\-52=(2i-3)(3+2i)a,\\ \\-52=(4i^2-9)a,\\ \\-52=(-4-9)a,\\ \\-13a=-52,\\ \\a=4.

Therefore,

p(x)=(x-(3-2i))(x-(3+2i))(x-4),\\ \\p(x)=(x^2-6x+13)(x-4),\\ \\p(x)=x^3-10x^2+37x-52.

3 0
3 years ago
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