All categories

3 years ago

Which equation has two real solutions? A. x^2-4=0 B. x-4=0 C. x^2-4=0 D. x+4=0

Mathematics

1 answer:

a_sh-v [17]3 years ago

7 0

Answer:

A and C (they are same equation)

x^2-4=0

x^2=4

x can be 2 and -2

2^2=4

-2^2=4

Step-by-step explanation:

prove

x-4=0

X=4 (one solution)

x+4=0

X=-4 (one solution)

You might be interested in

If x is located at -2 and y is located at -5, find Z such that XY is divided into a 2:1 ratio

DIA [1.3K]

Answer:

z = -4

Step-by-step explanation:

Given :

x = -2
y = -5
z divides xy in the ratio 2 : 1 (m : n)

Solving :

Take the section formula
z = [my + nx] / [m + n]
z = [2 x -5 + 1 x -2] / [2 + 1]
z = -10 - 2 / 3
z = -12 / 3
z = -4

5 0

3 years ago

Is (3,13) a solution of y = 2x - y

PtichkaEL [24]

Answer:

Step-by-step explanation:

(x, y) so if you plug in your points... 13 = 2(3) - 13

To solve:

Multiply: 13 = 2(3) - 13

Subtract: 13 = 6 - 13

Answer: 13 does not equal -7

5 0

3 years ago

DaMarcus says the number 24/6 belongs only to the set of rational numbers. Explain his error.

ElenaW [278]

24/6 = 4. The eror is that 4 is not only in the set of rational numbers, but is also part of natural numbers, integers, and whole numbers.

7 0

3 years ago

What is the simplified expression in standard form

Schach [20]

Answer:

$\boxed{\sf - 2 {p}^{2} - 11p - 35}$

Step-by-step explanation:

$\sf \implies - 2 {(p + 4)}^{2} - 3 + 5p \\ \\ \sf \implies - 2( {p}^{2} + 2(p)(4) + {4}^{2} ) - 3 + 5p \\ \\ \sf \implies - 2( {p}^{2} + 8p + 16) - 3 + 5p \\ \\ \sf \implies (( - 2) \times {p}^{2} ) + (( - 2) \times 8p) + ( ( - 2) \times 16) - 3 + 5p \\ \\ \sf \implies (- 2 {p}^{2} ) + ( - 16p ) + (- 32) - 3 + 5p \\ \\ \sf \implies - 2 {p}^{2} - 16p - 32 - 3 + 5p \\ \\ \sf \implies - 2 {p}^{2} + (- 16p + 5p) + ( - 32 - 3) \\ \\ \sf \implies - 2 {p}^{2} - 11p - 35$

4 0

4 years ago

I need help with this question!

alekssr [168]

Answer:

a) 2(x+12) and 2 times X+ 2 times 6

b) 12y+8

Step-by-step explanation:

for (A) the equation that i choose are the distributed from of the equation

for (B) I combined like terms and they only equation that made sense is this one

5 0

4 years ago