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3 years ago

Which equation has two real solutions? A. x^2-4=0 B. x-4=0 C. x^2-4=0 D. x+4=0

Mathematics

1 answer:

a_sh-v [17]3 years ago

7 0

Answer:

A and C (they are same equation)

x^2-4=0

x^2=4

x can be 2 and -2

2^2=4

-2^2=4

Step-by-step explanation:

prove

x-4=0

X=4 (one solution)

x+4=0

X=-4 (one solution)

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PilotLPTM [1.2K]

Answer:

<h3>The options A),B) and E) are correct</h3><h3>A) The given expression $p-\frac{2}{3}p$ is equivalent to $\frac{p}{3}$ </h3><h3>B) The given expression $\frac{p}{3}$ is equivalent to $\frac{p}{3}$ </h3><h3>E) The given expression $\frac{3p}{9}$ is equivalent to $\frac{p}{3}$ </h3>

Step-by-step explanation:

Given expression is $\frac{p}{3}$

<h3>To find the equivalent expressions to the given expression :</h3>

A) $p-\frac{2}{3}p$

Solving the expression $p-\frac{2}{3}p$

$p-\frac{2}{3}p=\frac{p(3)-2p}{3}$