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Reil [10]
3 years ago
11

a right triangle is removed from a rectangle to create the shaded region shown below. find the area of the shaded region. be sur

e to include the correct unit in your answer. ​

Mathematics
1 answer:
ser-zykov [4K]3 years ago
3 0

Answer:

36

Step-by-step explanation:

Objective: Find missing dimensions of the right triangle using the then subtract that area of the triangle from the rectangle's area.

Using the definition of a rectangle, the left vertical side measure is 7 and right vertical side is 6. So the missing legs of the triangle is 4 and 3.

Apply triangle formula, base x height divided by 2.

\frac{4 \times 3}{2}  = 6

Area of rectangle is length x width so the area is

7 \times 6 = 42

Subtract 6 from 42.

42 - 6 = 36

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Use trigonometry to find the missing side. Round your answer to the nearest tenth (one decimal place)
Alchen [17]

Given:

A figure of a right triangle.

To find:

The missing side by using the trigonometric ratios.

Solution:

In a right angle triangle,

\cos \theta=\dfrac{Adjacent}{Hypotenuse}

In triangle ABC,

\cos A=\dfrac{AC}{AB}

\cos (31^\circ)=\dfrac{b}{270}

0.857=\dfrac{b}{270}

Multiply both sides by 270.

0.857\times 270=b

231.39=b

b\approx 231.4

Therefore, the missing side length is b=231.4 inches.

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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(x +y )(x -y), if x = -3, y=-5<br> PLS NO FILES OR I AM REPORTING YOU
luda_lava [24]

Answer:

-16

Step-by-step explanation:

(X + Y)

= (-3 + -5)

= -8

(X - Y)

= (-3 - -5)

= 2

Because  they're still in brackets in this form:

(-8) (2)

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3 years ago
Determine if the function is linear, not linear.
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Y^3=x and 3y=x^2 is nonlinear

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According to a survey by the National Center for Health Statistics, the heights of adult men in the U.S. are normally distribute
fiasKO [112]

Answer:

0.0151 is the probability  that adult men are at most 59 inches or at least 74 inches.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 68 inches

Standard Deviation, σ = 2.75 inches

We are given that the distribution of heights of adult men is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(height between 59 and 74)

P(59 \leq x \leq 74) = P(\displaystyle\frac{59 - 68}{2.75} \leq z \leq \displaystyle\frac{74-68}{2.75}) = P(-3.2727 \leq z \leq 2.1818)\\\\= P(z \leq 2.1818) - P(z < -3.2727)\\= 0.9854 - 0.0005=98.49\%

P(x\leq59 \cup x\geq 74)=1 - P(59\leq x \leq 74) \\=1 - 0.9849\\=0.0151\\=1.51\%

0.0151 is the probability  that adult men are at most 59 inches or at least 74 inches.

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