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Reil [10]
2 years ago
11

a right triangle is removed from a rectangle to create the shaded region shown below. find the area of the shaded region. be sur

e to include the correct unit in your answer. ​

Mathematics
1 answer:
ser-zykov [4K]2 years ago
3 0

Answer:

36

Step-by-step explanation:

Objective: Find missing dimensions of the right triangle using the then subtract that area of the triangle from the rectangle's area.

Using the definition of a rectangle, the left vertical side measure is 7 and right vertical side is 6. So the missing legs of the triangle is 4 and 3.

Apply triangle formula, base x height divided by 2.

\frac{4 \times 3}{2}  = 6

Area of rectangle is length x width so the area is

7 \times 6 = 42

Subtract 6 from 42.

42 - 6 = 36

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8 0
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Please help me 33/2 + 3y/5 = 7y/10 + 15
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We are given with an equation in <em>variable y</em> and we need to solve for <em>y</em> . So , now let's start !!!

We are given with ;

{:\implies \quad \sf \dfrac{33}{2}+\dfrac{3y}{5}=\dfrac{7y}{10}+15}

Take LCM on both sides :

{:\implies \quad \sf \dfrac{165+6y}{10}=\dfrac{7y+150}{10}}

<em>Multiplying</em> both sides by <em>10</em> ;

{:\implies \quad \sf \cancel{10}\times \dfrac{165+6y}{\cancel{10}}=\cancel{10}\times \dfrac{7y+150}{\cancel{10}}}

{:\implies \quad \sf 165+6y=7y+150}

Can be <em>further written</em> as ;

{:\implies \quad \sf 7y+150=165+6y}

Transposing <em>6y </em>to<em> LHS</em> and <em>150</em> to<em> RHS </em>

{:\implies \quad \sf 7y-6y=165-150}

{:\implies \quad \bf \therefore \quad \underline{\underline{y=15}}}

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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