Andrew can buy maximum 3 meals this weekend.
From given question,
Andrew must spend less than 53$ on meals during the weekend.
He has already spent 21$ on meals costing 8$ average.
Let x, the number of meals
So, we get an inequality,
8x + 21 < 53
We need to find the number of meals he can buy this weekend.
From above inequality,
⇒ 8x + 21 < 53
⇒ 8x < 53 - 21
⇒ 8x < 32
⇒ x < 4
This means, from 1 to 3 meals.
Therefore, Andrew can buy maximum 3 meals this weekend.
Learn more about an inequality here:
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Answer:
73.3
Step-by-step explanation:
7%=7÷100=0.07 ×60=4.2
15%=15÷100=0.15×60=9
add you answers to 60 and to should get 73.2
Answer:
Square each number: 1 , 2 , 3 , 4 , 5:
1² = 1 * 1 = 1
2² = 2 * 2 = 4
3² = 3 * 3 = 9
4² = 4 * 4 = 16
5² = 5 * 5 = 25
~
8.3% is ur answer hope this helps
Answer:
e^2 -7 = x
Step-by-step explanation:
2=ln(x+7)
Raise each side to the base of e
e^2 = e^ln (x+7)
The e^ln cancel
e^2 = x+7
Subtract 7 from each side
e^2 -7 = x +7-7
e^2 -7 = x