Answer:
<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>
Step-by-step explanation:
First alloy contains 34% copper and the second alloy contains 48% alloy.
We wish to make 46 pounds of a third alloy containing 37% copper.
Let the weight of first alloy used be 
in pounds and the weight of second alloy used be 
in pounds.
Total weight = 
Total weight of copper = 
Subtracting 34 times first equation from second equation,
∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.
I believe it would be 6 ounces
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
The possibility of selecting a 4 characters long password consisting of 3 letters and one number if letters cannot be repeated and the password must end with a number is 156000
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more number and variables.
The possibility of selecting the password = 26 * 25 * 24 * 10 = 156000
The possibility of selecting a 4 characters long password consisting of 3 letters and one number if letters cannot be repeated and the password must end with a number is 156000
Find out more on equation at: brainly.com/question/2972832
#SPJ4
