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ryzh [129]
2 years ago
10

Please help ill give brainliest

Mathematics
2 answers:
den301095 [7]2 years ago
5 0

Answer:

i think its personally B

Step-by-step explanation:

Vadim26 [7]2 years ago
5 0

Answer:

My answer was deleted but

its the 2nd one

Step-by-step explanation:

You might be interested in
PLEASE HELP VERY URGENT
worty [1.4K]

Answer:

A. square root of a^2 + b^2 for both answers

Step-by-step explanation:

The first problem, we are given

a^2 + b^2 = c^2

What we do is solve for c.

sqrt(a^2 + b^2) = c

c = sqrt(a^2 + b^2)

For problem 2,

WE can apply the Pythagorean theorem because we have a right triangle.

The equations is

a^2 + b^2 = c^2 like the first problem

Solving gets us

sqrt(a^2 + b^2) = c

c = sqrt(a^2 + b^2)

3 0
1 year ago
Five and fifty-six<br> thousandths in decimal form
Lerok [7]

Answer:

0.056

Step-by-step explanation:

:) hope this helps

3 0
2 years ago
Read 2 more answers
What is the diameter of a circle with area of 113.04 square cm. use 3.14?<br><br><br> pls fast
galina1969 [7]

Answer:

diameter of a circle = 12cm

Step-by-step explanation:

Area of a circle = πr²

113.04 cm² = πr²

First, search for radius (r) :-

r = √(113.04/π)

r = 6 cm

As diameter is equals to 2×radius

The diameter of a circle = 2 × 6cm

Final answer = 12 cm

3 0
2 years ago
Read 2 more answers
A student needed to prepare 500mL of 1X TAE buffer to run a QC gel. The stock solution in the lab is 5X TAE. What volumes of sto
Xelga [282]

Answer:

you need 100ml of 5X TAE and 400ml of water.

Step-by-step explanation:

You need to use a rule of three:

C_1V_1=C_2V_2

where:

\left \{ {{C_1= 5X} \atop {C_2=1X}} \right.

and

\left \{ {{V_1 = V_{TAE}} \atop {V_2=500ml}} \right.

Therefore:

V_{TAE} = \frac{V_2*C_2}{C_1}

V_{TAE} = 100ml

Then just rest the TAE volume to the final Volume and you get the amount of water that you need to reduce the concentration.

3 0
2 years ago
Read 2 more answers
What is the focus of the parabola given the equation y=x^2+4x-1
IrinaK [193]
Let's first rewrite it in vertex form.
Start by completing the square.
y = x² + 4x + 4 - 4 - 1
y = (x + 2)² - 5
(x + 2)² = y + 5

Now, 4a = 1; a = \frac{1}{4}

So, the vertex form is (x + 2)² = 4(\frac{1}{4})(y + 5)
So, we know that the vertex is at (-2, -5).
Since it's a concave up parabola, we just have to change the y-value to find the focus.

∴ F(-2, -5 + \frac{1}{4})
F(-2, \frac{-19}{4})
3 0
2 years ago
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