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slavikrds [6]
2 years ago
12

I WILL MARK BRAINIEST

Mathematics
2 answers:
Mrac [35]2 years ago
8 0

Answer:

x=20

4=140

1=40

Step-by-step explanation:

7x=2×+100

5×=100

×=20

4=7(20)=140

1=180-140=40

gregori [183]2 years ago
5 0

Answer:

x=20

m<4=140

m<1=40

Step-by-step explanation:

to figure out angle 1 just subtract 140 from 180

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There are 40 people at Drake’s sweet sixteen party. Drake’s only rule is that everyone in the party must meet and shake each oth
Nonamiya [84]

Answer:

Given:

Total Number of people at the Drake’s sweet sixteen party = 40

Everyone in the party must meet and shake each other’s hand

1) How many handshakes are there altogether?

There was total of 780 handshakes in the party.

2. How did you get your solution:

If you have 7 people, person seven shakes six other hands, person  

six shakes five other hands, person five shakes fours other hands,  

person  ,four shakes three other hands, person three shakes two other hands,  and person two shakes one hand.  Another way to see it is,

Person 7  +person 6 + person 5 + person 4 +person 3 + person 2 +  person 1

= 6+5+ 4+3+2+1

=>21

so similairly in case of 40 persons

= 39+38+37+36+37+36+35+34 .................+3+2+1

=>780

3) What’s the quickest way to figure this out if Drake invited 1,000 people?

People at Party               Number of Handshakes

     2                                                     1

     3                              1 + 2              = 3

     4                            1 + 2 + 3          = 6

     5                          1 + 2 + 3 + 4      = 10

     6                        1 + 2 + 3 + 4 + 5  = 15

     .

     .

     .                                          

     n                              1 + 2 + ...+ (n-1) =  --------     \frac{n(n-1)}{2}

Hence for n persons the number of handshakes will be  \frac{n(n-1)}{2}

So for 1000 persons the number of handshakes will be

=>\frac{1000(1000-1)}{2}

=>\frac{1000(999)}{2}

=>\frac{999000}{2}

=>499,500

                                                     

3 0
3 years ago
The number on two consecutively numbered gym lockers have a sum of 127. What are the locker numbers?
kaheart [24]
63 and 64 is the answer
4 0
2 years ago
Hugo recurved $100 for his birthday.He then saves 20$ per week until he had a total of $460 to buy a printer. Use a. Equation to
SashulF [63]

Answer:

18 weeks

Step-by-step explanation:

In this question, we are asked to use an equation to show the number of weeks it took Hugo who received a certain amount in his birthday and continually saved a certain amount before he could gather a certain amount of money.

In this question, we understand that Hugo wants to buy a printer that costs $460. Fortunately, he had his birthday and he received $100 bucks. Now, let’s say the number of weeks he had to save for is w and he saves 20 per week. This means the total amount he hit from his savings would be 20w

Mathematically, we can use the equation below to model this scenario;

100 + 20(w) = 460

20w = 460 - 100

20w = 360

w = 360/20

w = 18 weeks

3 0
3 years ago
What is the slope of a line perpendicular to the line whose equation is 3x+6y=-183x+6y=−18. Fully reduce your answer.
schepotkina [342]

Answer:

2

Step-by-step explanation:

The given equation of line is

3x+6y=-18

We need to find the slope of a line which is perpendicular to the given line.

The given equation can be rewritten as

3x+6y+18=0      ...(i)

If a line is defined as ax+bx+c=0, then the slope of the line is  

m=-\dfrac{a}{b}

In equation (i), a=3, b=6 and c=18. So, slope of the line is

m_1=-\dfrac{3}{6}=-\dfrac{1}{2}

Let m_2 be the slope of perpendicular line.

We know that product of two perpendicular line is -1.

m_1\cdot m_2=-1

(-\dfrac{1}{2})\cdot m_2=-1

Multiply both sides by -2.

m_2=2

Therefore, the slope of perpendicular line is 2.

6 0
3 years ago
Bye guys im quitting, it was fun while it lasted thanks everybody for being here
nalin [4]

Answer:

Not sure if I was ever able to help you but I hope you have an amazing future<#

3 0
3 years ago
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