There are nine possible combinations as follows: bb, bc, bt, cb, cc, ct, tb, tc, tt, each having a probability of 1/9. The four combinations with a cab exactly one time are: bc, cb, ct, tc. Therefore the probability that she'll use a cab exactly one time is: 4/9.
1.46 points put them all in to decimals so 4.26-3.5= .76 + .7 is 1.46
Answer:it’s b
Step-by-step explanation:
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