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3 years ago

Please help!!! i would really apreciate it

Mathematics

1 answer:

postnew [5]3 years ago

3 0

Answer:

it should be the graph on the bottom right

Step-by-step explanation:

The income should be more than the cost in order to make a profit and that happens for Leanne when she sells 8 quilts, so the 8 should be on the x-axis (the axis named "Quilts Sold")

The income should be 0 in the beginning bc when she sells 0 quilts she will be earning 0.

after selling 8 quilts her income will be higher than her costs

(Though naming the y-axis as "profit" is not accurate bc when she sells 0 quilts she will lose money since she will be spend money to make the quilts but not earn the money to compensate for the cost).

with all of these reasons combined the correct should be the one on the bottom right

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3x+7y=-6<br> 7x+3y=26<br> solve by elimenation

Artemon [7]

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3 years ago

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baherus [9]

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Step-by-step explanation:

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4 0

3 years ago

A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa

Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion

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Hypotheses are:

$H_{0}$ : p(public) = p(private)

$H_{a}$ : p(public) ≠ p(private)

The formula for the test statistic is given as:

z= $\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of public university students who attended at least one class reunion ( $\frac{808}{1311}=0.616$ )

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n2 is the sample size of the students from private university (1038)

Then z= $\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}}$ =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.

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3 years ago

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katovenus [111]

Answer:

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Step-by-step explanation:

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arlik [135]

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