With amounts measured in gallons, let
x = amount of 65% antifreeze
y = amount of 90% antifreeze
1 gal of the 65% brand contains 0.65 gal of pure antifreeze; x gal would contain 0.65x gal. Similarly, y gal of the 90% brand contains 0.90y gal of pure antifreeze.
To obtain 120 gal of 80% antifreeze solution (which contains 0.80•120 = 96 gal of pure antifreeze), we must have
x + y = 120 … … … … … [total volume of antifreeze solution]
0.65x + 0.90y = 96 … [total volume of pure antifreeze]
Solve the first equation for y :
y = 120 - x
Substitute this into the second equation and solve for x :
0.65x + 0.90 (120 - x) = 96
0.65x + 108 - 0.90x = 96
0.25x = 12
x = 48
Solve for y :
y = 120 - 48
y = 72
Answer:

Step-by-step explanation:
This question is illustrated using the attachment and will be solved using cosine formula

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The cosine formula in this case is:

Where



The equation becomes



Collect Like Terms


Using quadratic formula:

Where







or 
or 
or 
But length can not be negative.
So:

The answer to your question is A but i dont see a D option so it might be wrong
3 x 6 x 9 x 3 x 6 x 9 = ?
3 x 6 = 18
18 x 9 = 162
162 x 3 = 486
486 x 6 = 2,916
2,916 x 9 = 26,244
3 x 6 x 9 x 3 x 6 x 9 = 26,244