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3 years ago

Ok if I have 159 booklets to do and I do 12 in a year how many years will it take to finish all the booklets?

Mathematics

1 answer:

never [62]3 years ago

7 0

Answer:

13.25 years

Step-by-step explanation:

Take the number of booklets and divide by the number of booklets per year

159/12

13.25 years

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Need help I'm getting it wrong I don't understand

ivanzaharov [21]

W/3-15=12
remember, you can do ANYTHING to an equaiton as long as you do it to both sides
get w by itself

$\frac{w}{3}-15=12$
add 15 to both sides
$\frac{w}{3}+15-15=12+15$
$\frac{w}{3}+0=27$
$\frac{w}{3}=27$
tiemes both sides by 3/1
$\frac{3w}{3}=27*3$
$(\frac{3}{3})w=81$
$1w=81$
$w=81$

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4 years ago

Please help with this!

Mnenie [13.5K]

Answer: see attachment

<u>Step-by-step explanation:</u>

5 0

3 years ago

Show your work as you go along.

lana66690 [7]

2x+3(2x-4y)+8y-2
2x+6x-12y+8y-2
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8x-4y-2

8 0

4 years ago

PLEASE HELP<br> Simplify the expression to a + bi form:<br> √ 25- √ -25 – √ 36 – √ -4

klasskru [66]

Answer:

-1+3i

Step-by-step explanation:

$\sqrt{25} - \sqrt{ - 25} - \sqrt{36} - \sqrt{ - 4}$

Sqr root of 25 and 36 are 5 and 6 respectively

Sqr root of -25 and -4 are 5i and 2i respectively

Combine like with like

5-6=-1

5i-2i=3i

-1+3i

7 0

3 years ago

Point B is 2/3 the way from A(-2,5)to C(4,-4). Find the location of B

mr Goodwill [35]

well, we'll first off put the point AC in component form by simply doing a subtraction of C - A, multiply that by the fraction 2/3, and that result will get added to point A, to get point B.

$\bf \textit{internal division of a segment using a fraction}\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-4})~\hfill \frac{2}{3}\textit{ of the way from }A\to C \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_2}{4}-\stackrel{x_1}{(-2)}, \stackrel{y_2}{-4}-\stackrel{y_1}{5})\implies (4+2,-9) \stackrel{\textit{component form of segment AC}}{\qquad \implies \qquad (6,-9)} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{~\hfill \textit{coordinates to be added to point A}} {\cfrac{2}{3}(6,-9)\implies \cfrac{2}{3}(6)~,~\cfrac{2}{3}(-9)\qquad \implies \qquad \left(4,-6\right)} \\\\\\ \stackrel{\textit{additions to point A}} {\stackrel{\textit{point A}}{(-2,5)}+\left( 4,-6\right)}\implies \left( -2+4~~,~~5-6\right) = B\implies (2~,~-1)=B$

5 0

3 years ago