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3 years ago

What are the common factors of 11,22 and 33

Mathematics

1 answer:

jarptica [38.1K]3 years ago

8 0

Answer:

11 and 1

Step-by-step explanation:

11: 11/1

22: 11/1/2/22

33: 11/1/33/3

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What is the area of a circular cardboard piece needed for the base of a model of a volcano that is 20 centimeters tall and has a

Shkiper50 [21]

Answer:

The answer is d for reaaal

Step-by-step explanation:

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3 years ago

Read 2 more answers

Giselle works as a carpenter and as a blacksmith. She earns \$20$20dollar sign, 20 per hour as a carpenter and \$25$25dollar sig

Pani-rosa [81]

She earns 20 dollars as a carpenter and 25 dollars as a blacksmith

b+c=30 hours since she works 30 hours a week

25b+20c=690 since she earns 690 dollar totally and earns 25 dollars an hour as a blacksmith and 20 dollars an hour as a carpenter

lets multiply b+c=30 by -20

-20b-20c=-600

if we substract that from

25b+20c=690

5b=90

b=18 she worked as a blacksmith for 18 hours

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3 years ago

You estimated the average rental cost of a 2 bedroom apartment in Denton. A random sample of 16 apartments was taken. The sample

Zigmanuir [339]

Answer:

The new sample size required in order to have the same confidence 95% and reduce the margin of erro to $60 is:

n=28

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma=160)$

And the distribution for $\bar X$ is:

$\bar X \sim N(\mu, \frac{160}{\sqrt{n}})$

We know that the margin of error for a confidence interval is given by:

$Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The next step would be find the value of $\z_{\alpha/2}$ , $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$

Using the normal standard table, excel or a calculator we see that:

$z_{\alpha/2}=\pm 1.96$

If we solve for n from formula (1) we got:

$\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}$

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

And we have everything to replace into the formula:

$n=(\frac{1.96(160)}{78.4})^2 =16$

And this value agrees with the sample size given.

For the case of the problem we ar einterested on Me= $60, and we need to find the new sample size required to mantain the confidence level at 95%. We know that n is given by this formula:

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

And now we can replace the new value of Me and see what we got, like this:

$n=(\frac{1.96*160}{60})^2 =27.32$

And if we round up the answer we see that the value of n to ensure the margin of error required $Me=\pm 60$ $ is n=28.

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3 years ago

How does a digit in the ten thousand place compare to a digit in the thousands place

Butoxors [25]

A digit in the ten thousand place has a value of 10,000 times the value of the mere digit. While a digit in the thousands place has a value 1,000 times the value of the digit. So to compare you can do 10,000 / 1,000 = 10, which means that<span> a digit in the ten thousand place values ten times what the same digit values is it is the thousand place. </span>

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3 years ago

Where am I to put the points? help?

maria [59]

we know that a has to be a number less than 0 and c has to be a number greater than 0. so a has to go before the number 0 and b can go before or after 0, as long as it satisfies the equation

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3 years ago