189 : 24 = 7 r 21
------------------------
Answer:
Probability (bid accepted) = 0.48
Step-by-step explanation:
Probability density is given byF(y)= 1/(b-a)
a=9500
b= 14700
F(y)= 1/(14700-9500) =1/5200=0.00019
Probability (bid accepted)= (12000-9500)÷1/5200
P( bid accepted) = 2500×0.00019=0.475 approximately 0.48
Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
The correct answer to this question is 240
From the image i've seen, the RDC has an angle of 120. So the major arc DC (that passes A and B) has an angle of 240.
So this makes that the measure of the angle of DAC is 240 because of the angle formed by RDC which is 120.
Mean: 48.7
Median: 38
Mode:55