It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
The graph starts flat but then curves steeply upwards. You can tell this by the sudden jumps in y-coordinates, illustrating that it keeps going further up faster and faster as the x-coordinates progress steadily.
ANSWER:
6_34/99
STEP:
So yes. When a decimal is repeating, you can take the repeating number (most likely a decimal) and put 99 under it. Since 99 cannot be solved, you put 99. So, 34/99. Though we are not finished. There is still the whole 6 number left. So, you do 6_34/99.
Proof:
10x=6.6...
-x=-0.6...
9x=6
x=6/9=1/3.
Answer: the first one
Step-by-step explanation: just trust me ;)
The answers are:
<span>ƒ(x) = x - .15x
</span><span>Sale = Original - .15(Original)
</span><span>y = .85x
Let sale price be f(x) and x be the original price. Discount was 15% = 0.15
f(x) = x - 0.15x
If f(x) is sale and x is the original, then:
</span><span>Sale = Original - .15(Original)
Let sale price be y and original price x:
y = x - 0.15x
y = 1 * x - 0.15 * x
y = (1 - 0.15) * x
y = 0.85x</span>
