2 consecutive integers...x and x + 1
x + x + 1 < = 3
2x + 1 < = 3
2x < = 3 - 1
2x < = 2
x < = 1
x + 1 = 1 + 1 = 2.......the greatest possible value for the greatest integer is 2
Answer:
7 :)
Step-by-step explanation:
8 boxes is 100%, 6 out of 8 is 6/8 x 100% = 75%
Answer:
8
Step-by-step explanation:
let the number be n , then
n + 3 = n - 3 ( multiply through by 4 to clear the fraction )
n + 12 = 4n - 12 ( subtract 4n from both sides )
- 3n + 12 = - 12 ( subtract 12 from both sides )
- 3n = - 24 ( divide both sides by - 3 )
n = 8
That is the number is 8
A=s^2 50=S^2 s= sqrt50 s=7.071 ms a^2+a^2=c^2 50+50=c^2 100=c^2 c= sqrt100 c=10ms So the answer would be 10 hope this helped
