Answer:
Internet is the correct answer for the above question.
Explanation:
- The Internet Explorer define some security zone (which includes the Restricted sites, internet, Trusted sites, and Local intranet) which is used to block the unwanted sites which can be opened by some other websites.
- When any user use any website, sometimes that websites open different websites. This security zone gives the features to secure the user from this event.
- There are four-zone which are described in the first line, in which the internet zone is used to take all the websites which are not defined for the other security zone. It means that when any user does not decide the security zone for any websites then by default it comes in the internet zone.
- This is also asked by the question, Hence "internet" is the correct answer.
Using the computer language in python to write a function code that personalized house signs
<h3>Writting the code in python:</h3>
<em>#Assign varibles</em>
<em>charge = 0.00</em>
<em>numChars = 8</em>
<em>color = "gold"</em>
<em>woodType = "oak"</em>
<em />
<em>#Checking for number of characters</em>
<em>if numChars > 5:</em>
<em>charge = 35 + (numChars-5)*4</em>
<em>elif numChars > 0:</em>
<em>charge = 35</em>
<em />
<em>#Checking wood type</em>
<em>if woodType == "oak":</em>
<em>charge += 20</em>
<em />
<em>#Checking for color</em>
<em>if color == "gold":</em>
<em>charge += 15</em>
<em />
<em>#Print output</em>
<em>print("The charge for this sign is $"+str(charge)+".")</em>
See more about python at brainly.com/question/13437928
#SPJ1
Answer:
- def check_subset(l1, l2):
- status = False
- count = 0
- if(len(l1) > len(l2)):
- for x in l2:
- for y in l1:
- if x == y:
- count += 1
-
- if(count == len(l2)):
- return True
- else:
- return False
-
- else:
- for x in l1:
- for y in l2:
- if x==y:
- count += 1
-
- if(count == len(l1)):
- return True
- else:
- return False
-
- print(check_subset([1,4,6], [1,2,3,4,5,6]))
- print(check_subset([2,5,7,9,8], [7,8]))
- print(check_subset([1, 5, 7], [1,4,6,78,12]))
Explanation:
The key idea of this solution is to create a count variable to track the number of the elements in a shorter list whose value can be found in another longer list.
Firstly, we need to check which list is shorter (Line 4). If the list 2 is shorter, we need to traverse through the list 2 in an outer loop (Line 5) and then create another inner loop to traverse through the longer list 1 (Line 6). If the current x value from list 2 is matched any value in list 1, increment the count variable by 1. After finishing the outer loop and inner loop, we shall be able to get the total count of elements in list 2 which can also be found in list 1. If the count is equal to the length of list 2, it means all elements in the list 2 are found in the list 1 and therefore it is a subset of list 1 and return true (Line 10-11) otherwise return false.
The similar process is applied to the situation where the list 1 is shorter than list 2 (Line 15-24)
If we test our function using three pairs of input lists (Line 26-28), we shall get the output as follows:
True
True
False
5(3x - 7)
distribute the 5 to both 3x and -7
15x - 35 is equivalent
hope this helps
