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elena-s [515]
2 years ago
13

What describes Accenture's approach to automation?

Computers and Technology
1 answer:
Mrrafil [7]2 years ago
4 0
<h2>Answer:</h2>

<h2>intelligence - centered</h2>

<h2>Explanation:</h2>

I hope it helps you

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Write a loop that reads positive integers from standard input and that terminates when it reads an integer that is not positive.
Paraphin [41]

Answer:

The program to this question as follows:

Program:

#defining variable and assign value

odd=0  

even=0  

i=1  

print('Input 0 after inserting all number: ') #print message

while i>0: #define loop for check inserting and add all number

   i=int(input()) #input value by user end

   if (i< 0): #check value is not positive

       break

   if ((i % 2)==0and(i>0)): #check even number condition

       even=even+i #add even numbers

   if ((i % 2)!=0and(i>0)): #check odd number condition

       odd=odd+i #add odd numbers

print ('Sum of Even number:',even,'and','Sum of Odd number:',odd) #print value

Output:

Input 0 after inserting all number:  

1

2

3

5

7

0

Sum of Even number: 2 and Sum of Odd number: 16

 Explanation:

In the above python program, three variable is defined, that is "even, odd and i", in which "even and odd" variable assign value that is "0", and the variable i is used for inserting elements from user. In the next line a while loop is defined that inserts numbers in variable "i", in this loop, 3 if block is used that can be defined as follows:

  • In first if block variable "i", checks that value is non-positive number if this condition is true, it will break the loop.
  • In second if block this block check even number condition and add in even variable.
  • In third, if block this block check odd number condition and add in odd variable.  

End of the loop we use print function that prints the sum of even numbers and odd numbers.

3 0
3 years ago
When microsoft introduced its zune mp3 player, many people thought it would capture the mp3 player market by pricing its product
SSSSS [86.1K]
Your answer would be:  P<span>redatory Pricing .</span>
8 0
3 years ago
What is the final gear reduction of a compound gear reduction of 36 to 12 for the first stage and 60 to 12 for the second stage?
OverLord2011 [107]

Answer:

8

Explanation:

Gear reduction = driven gear teeth / driving gear teeth

First stage reduction :

Driven gear teeth = 36

Driving gear teeth = 12

36 /12 = 3

Second stage reduction :

Driven gear teeth = 60

Driving gear teeth = 12

60 /12 = 5

First stage + second stage

3 + 5 = 8

5 0
3 years ago
If there are 8 opcodes and 10 registers, a. What is the minimum number of bits required to represent the OPCODE? b. What is the
Nimfa-mama [501]

Answer:  

For 32 bits Instruction Format:

OPCODE   DR               SR1                   SR2      Unused bits

a) Minimum number of bits required to represent the OPCODE = 3 bits

There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.

Ceil (log2 (8)) = 3

b) Minimum number of bits For Destination Register(DR) = 4 bits

There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value.  4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.  

Ceil (log2 (10)) = 4

c) Maximum number of UNUSED bits in Instruction encoding = 17 bits

Total number of bits used = bits used for registers + bits used for OPCODE  

     = 12 + 3 = 15  

Total  number of bits for instruction format = 32  

Maximum  No. of Unused bits = 32 – 15 = 17 bits  

OPCODE                DR              SR1             SR2              Unused bits

  3 bits              4 bits          4 bits           4 bits                17 bits

7 0
3 years ago
Read the following example cover letter:
enot [183]

Answer:

All should be added.

Explanation:

All of these are important to your cover letter to make it seem professional.

Hope this helped

3 0
3 years ago
Read 2 more answers
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