# of ways to pick 3 "acceptable": 10C3 = 120
# of ways to pick 1 not acceptable: 5C1 = 5
# of ways to pick 4 where exactly 3 are acceptable: 120*5 = 600
<span># of ways to pick 4 with no restrictions: 15C4 = 1365</span>
Step-by-step explanation:
2s +5>49
2s >49-5
2s>44
S>44÷2
S>22
34 + 37 is a simplified version of the previous question