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Softa [21]
3 years ago
10

Describe the end behavior of the graphed function

Mathematics
1 answer:
Troyanec [42]3 years ago
5 0

You have to consider the “ends” of the x-axis, the far right (for infinitely large values of x) and left (for infinitely small values of x) of the graph.

From the diagram above you can see that:

  1. When x\rightarrow -\infty, then y=f(x)\rightarrow 1 (notice that as the values of x get smaller and smaller, the graph gets closer and closer to the line y=1);
  2. When x\rightarrow \infty, then y=f(x)\rightarrow 1. (notice that as the values of x get larger and larger, the graph gets closer and closer to the line y=1).

Answer: correct choice is D.

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natulia [17]

Answer:

1/2

Step-by-step explanation:

3 0
3 years ago
Help again...its for math offering 15 points
Anettt [7]

Answer:

\tan \dfrac{\theta}2 = \dfrac{1}2

Step by step Explanation:

\sin \theta = \dfrac{\text{Perpendicular} }{\text{Hypotenuse}} = \dfrac{12}{15}\\\\\\\cos \theta = \dfrac{\text{Base}}{\text{Hypotenuse}}= \dfrac{9}{15}\\\\\text{Now,}\\\\\tan \dfrac{\theta}2 = \dfrac{\sin \tfrac{\theta}2}{\cos \tfrac{\theta}2}\\\\\\~~~~~~~~=\dfrac{2\cos \tfrac{\theta}2 \sin \tfrac{\theta}2 }{2\cos^2 \tfrac{\theta}2}~~~~~~;\left[\text{Multiply by}~ 2\cos\tfrac{\theta}2 \right]

         =\dfrac{\sin \theta}{1+ \cos \theta}~~~~~~~~~~~~;[2 \sin x \cos x = \sin 2x ~ \text{and}~ 2\cos^2 x =1+\cos 2x]\\\\\\=\dfrac{\tfrac{12}{15}}{1+ \tfrac{9}{15}}\\\\\\=\dfrac{\tfrac{12}{15}}{\tfrac{24}{15}}\\\\\\=\dfrac{12}{15}\times \dfrac{15}{24}\\\\\\=\dfrac{12}{24}\\\\\\=\dfrac{1}2

4 0
2 years ago
After grabbing some food from the cafeteria, Ray trips causing his food to go up in the air before hitting the ground. The parab
Dahasolnce [82]

The maximum height of the tray is 1.8 meters and the tray is in the air for 2 seconds

<h3>The maximum height of the tray</h3>

The distorted information (i.e. the function) in the question is:

h(t) = -0.2t^2 + 0.4t + 1.6

Differentiate the function

h'(t) = -0.4t + 0.4

Set to 0

-0.4t + 0.4 = 0

Subtract 0.4 from both sides

-0.4t = -0.4

Divide by -0.4

t = 1

Substitute t = 1 in h(t) = -0.2t^2 + 0.4t + 1.6

h(1) = -0.2(1)^2 + 0.4(1) + 1.6

Evaluate

h(1) = 1.8

Hence, the maximum height of the tray is 1.8 meters

<h3>Time spent in the air</h3>

In (a), we have:

t = 1

This represents the time to reach the maximum height.

The time spent in the air is:

T = 2t

This gives

T = 2 * 1

T = 2

Hence, the tray is in the air for 2 seconds

Read more about quadratic functions at:

brainly.com/question/11535666

#SPJ1

7 0
2 years ago
How do u simplify this: sqrt =square root<br> 2sqrt462cd^2 * sqrt7c^5d^2
Sveta_85 [38]

Answer: The simplified version of this is 14d²c³√66

Step-by-step explanation:

6 0
3 years ago
Which values of a and b make the following equation true?  a = 11, b = 7 a = 11, b = 10 a = 28, b = 7 a = 28, b = 10
lora16 [44]
A = 11, b = 7
You just needed to multiply the terms together
6 0
3 years ago
Read 2 more answers
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