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ArbitrLikvidat [17]
2 years ago
6

Which of the following is an example of an exponential equation?

Mathematics
1 answer:
KatRina [158]2 years ago
3 0

Answer:

Option D

Step-by-step explanation:

y = 2(3)^x is the example of exponential equation.

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Figure TUVW ≅ figure ABCD, AB = 12, CD = 6, and DA = 4.
Olegator [25]
The measure of VW is 6. It's because since the figures are congruent their names are written in correspondence ....so since VW corresponds to CD , the answer must be 6.
6 0
3 years ago
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00:00
Furkat [3]

Answer:

-2

Step-by-step explanation:

Subtracting a negative number is the same as adding it, so this is basically just negative 8 plus 6, which is -2. Don't know who was right though, you kinda left that part of the question out.

5 0
3 years ago
Suppose that x and y are both differentiable functions of t and are related by the given equation. Use implicit differentiation
stepan [7]

Answer:

Let z = f(x, y) where f(x, y) =0 then the implicit function is

\frac{dy}{dx} =\frac{-δ f/ δ x }{δ f/δ y }

Example:- \frac{dy}{dx}  = \frac{-(y+2x)}{(x+2y)}

Step-by-step explanation:

<u>Partial differentiation</u>:-

  • Let Z = f(x ,y) be a function of two variables x and y. Then

\lim_{x \to 0} \frac{f(x+dx,y)-f(x,y)}{dx}    Exists , is said to be partial derivative or Partial differentiational co-efficient of Z or f(x, y)with respective to x.

It is denoted by δ z / δ x or δ f / δ x

  • Let Z = f(x ,y) be a function of two variables x and y. Then

\lim_{x \to 0} \frac{f(x,y+dy)-f(x,y)}{dy}    Exists , is said to be partial derivative or Partial differentiational co-efficient of Z or f(x, y)with respective to y

It is denoted by δ z / δ y or δ f / δ y

<u>Implicit function</u>:-

Let z = f(x, y) where f(x, y) =0 then the implicit function is

\frac{dy}{dx} =\frac{-δ f/ δ x }{δ f/δ y }

The total differential co-efficient

d z = δ z/δ x +  \frac{dy}{dx} δ z/δ y

<u>Implicit differentiation process</u>

  • differentiate both sides of the equation with respective to 'x'
  • move all d y/dx terms to the left side, and all other terms to the right side
  • factor out d y / dx from the left side
  • Solve for d y/dx , by dividing

Example :  x^2 + x y +y^2 =1

solution:-

differentiate both sides of the equation with respective to 'x'

2x + x \frac{dy}{dx} + y (1) + 2y\frac{dy}{dx} = 0

move all d y/dx terms to the left side, and all other terms to the right side

x \frac{dy}{dx}  + 2y\frac{dy}{dx} =  - (y+2x)

Taking common d y/dx

\frac{dy}{dx} (x+2y) = -(y+2x)

\frac{dy}{dx}  = \frac{-(y+2x)}{(x+2y)}

7 0
3 years ago
What is the following product 3 sqrt 2(5 sqrt 6-7 sqrt 3)
Licemer1 [7]
3\sqrt2\cdot(5\sqrt6-7\sqrt3)=3\cdot5\cdot\sqrt{2\cdot6}-3\cdot7\cdot\sqrt{2\cdot3}\\\\=15\sqrt{12}-21\sqrt6=15\sqrt{4\cdot3}-21\sqrt6=15\cdot\sqrt4\cdot\sqrt3-21\sqrt6\\\\=15\cdot2\cdot\sqrt3-21\sqrt6=\boxed{30\sqrt3-21\sqrt6}
Used:\\\sqrt{a}\cdot\sqrt{b}=\sqrt{a\cdot b}

8 0
3 years ago
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The probability of selecting an orange marble is 20%
zubka84 [21]

See there is no pink

So probability of selecting a pink is 0 .

The probability of orange is 20% or 0.2

The probability of purple is 30% or 0.3

As there is no color mentioned for rest part at max probability of pink is 0.5 .

  • But by now it's 0 as it's not mentioned
5 0
2 years ago
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