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mrs_skeptik [129]
3 years ago
15

Simplify the expression: 6 + 3(x + 4)

Mathematics
2 answers:
ohaa [14]3 years ago
8 0
Answer 3x+18
HOPEEE THISSS HELPPPSS!!!!!!!!!!!!!!

quester [9]3 years ago
3 0

Answer:

I think its the 3rd one...

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If 70% of a number is 42 and 15% of the same number is 9, find 85% of that number.
BigorU [14]

Answer:  51

Step-by-step explanation:

let x be the number.

(70%)x = 42

0.7 x = 42

x = 60

we check 15% x 60 = 0.15 x 60 = 9, which is true.

85% of that number = 85% x 60 = 0.85 x 60 = 51.

6 0
3 years ago
Read 2 more answers
Solve the problem, calculate the line integral of f along h
Over [174]
The curve \mathcal H is parameterized by

\begin{cases}X(t)=R\cos t\\Y(t)=R\sin t\\Z(t)=Pt\end{cases}

so in the line integral, we have

\displaystyle\int_{\mathcal H}f(x,y,z)\,\mathrm ds=\int_{t=0}^{t=2\pi}f(X(t),Y(t),Z(t))\sqrt{\left(\frac{\mathrm dX}{\mathrm dt}\right)^2+\left(\frac{\mathrm dY}{\mathrm dt}\right)^2+\left(\frac{\mathrm dZ}{\mathrm dt}\right)^2}\,\mathrm dt
=\displaystyle\int_0^{2\pi}Y(t)^2\sqrt{(-R\sin t)^2+(R\cos t)^2+P^2}\,\mathrm dt
=\displaystyle\int_0^{2\pi}R^2\sin^2t\sqrt{R^2+P^2}\,\mathrm dt
=\displaystyle\frac{R^2\sqrt{R^2+P^2}}2\int_0^{2\pi}(1-\cos2t)\,\mathrm dt
=\pi R^2\sqrt{R^2+P^2}

You are mistaken in thinking that the gradient theorem applies here. Recall that for a scalar function f:\mathbb R^n\to\mathbb R, we have gradient \nabla f:\mathbb R^n\to\mathbb R^n. The theorem itself then says that the line integral of \nabla f(x,y,z)=\mathbf f(x,y,z) along a curve C parameterized by \mathbf r(t), where a\le t\le b, is given by

\displaystyle\int_C\mathbf f(x,y,z)\,\mathrm d\mathbf r=f(\mathbf r(b))-f(\mathbf r(a))

Specifically, in order for this theorem to even be considered in the first place, we would need to be integrating with respect to a vector field.

But this isn't the case: we're integrating f(x,y,z)=y^2, a scalar function.
7 0
3 years ago
Which answer shows these decimals written in order from greatest to least?   76.493   79.2    76.81        A. 79.2 > 76.493 &
Aliun [14]
The answer is C 79.2 > 76.81 > 76.493
6 0
3 years ago
Please help I will fail if I don’t get this right
umka21 [38]
Answer:
J'(-4, -1)
K'(-2, -5)
L'(2, -5)
M'(3, -1)
Step-by-step explanation:
Reflection over the line y=1 is equivalent to the transformation ...
(x, y) ⇒ (x, 2-y)
Then the transformed coordinates are ...
J(-4, 3) ⇒ J'(-4, -1)
K(-2, 7) ⇒ K'(-2, -5)
L(2, 7) ⇒ L'(2, -5)
M(3, 3) ⇒ M'(3, -1)
6 0
3 years ago
In a local ice sculpture contest, one group sculpted a block into a rectangular based pyramid. The dimensions of the base were 3
m_a_m_a [10]

Answer:

1. The amount of ice needed = 18 m²

2. The amount of fabric needed to manufacture the umbrella is 0.76 m²

3. The height of the cone, is 3.75 cm

4. The dimensions of the deck are;

Width = 28/3 m, breadth = 28/3 m

The area be 87.11 m²

5.   The dimensions of the optimal design for setting the storage area at the corner, we have;

Width = 10m

Breadth = 10 m

The dimensions of the optimal design for setting the storage area at the back of their building are;

Width = 7·√2 m

Breadth = 7·√2 m

Step-by-step explanation:

1. The amount of ice needed is given by the volume, V, of the pyramid given by V = 1/3 × Base area × Height

The base area = Base width × Base breadth = 3 × 5 = 15 m²

The pyramid height = 3.6 m

The volume of the pyramid = 1/3*15*3.6 = 18 m²

The amount of ice needed = 18 m²

2. The surface area of the umbrella = The surface area of a cone (without the base)

The surface area of a cone (without the base) = π×r×l

Where:

r = The radius of the cone = 0.4 m

l = The slant height = √(h² + r²)

h = The height of the cone = 0.45 m

l = √(0.45² + 0.4²) = 0.6021 m

The surface area = π×0.4×0.6021 = 0.76 m²

The surface area of a cone (without the base) = 0.76 m²

The surface area of the umbrella = 0.76 m²

The amount of fabric needed to manufacture the umbrella = The surface area of the umbrella = 0.76 m²

3. The volume, V, of the cone = 1/3×Base area, A, ×Height, h

The volume of the cone V = 150 cm³

The base area of the cone A = 120 cm²

Therefore we have;

V = 1/3×A×h

The height of the cone, h = 3×V/A = 3*150/120 = 3.75 cm

4. Given that the deck will have railings on three sides, we have;

Maximum dimension = The dimension of a square as it is the product of two  equal maximum obtainable numbers

Therefore, since the deck will have only three sides, we have that the length of each side are equal and the fourth side can accommodate any dimension of the other sides giving the maximum dimension of each side as 28/3

The dimensions of the deck are width = 28/3 m, breadth = 28/3 m

The area will then be 28/3×28/3 = 784/9 = 87\frac{1}{9} =87.11 m²

5. The optimal design for setting the storage area at the corner of their property with four sides is having the dimensions to be that of of a square with equal sides of 10 m each as follows;

Width = 10m

Breadth = 10 m

The optimal design to have the storage area at the back of their building having a fence on only three sides, is given as follows;

Storage area specified = 98 m²

For optimal use of fencing, we have optimal side size of fencing = s = Side length of a square

s² = 98 m²

Therefore, s = √98 = 7·√2 m

Which gives the width = 7·√2 m and the breadth = 7·√2 m.

8 0
3 years ago
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