Answer: 46 years
Step-by-step explanation:
Let the father's age be x and the son's age be y, then 3 years ago:
Father = x - 3
son = y - 3
Then , from the first statement :
x - 3 = 3 ( y - 3 )
x - 3 = 3y - 9
x = 3y - 9 + 3
x = 3y - 6 .......................................... equation 1
In five years time
father = x + 5
son = y + 5
Then , from the second statement
x + 5 = 2 ( y + 5 )
x + 5 = 2y + 10
x = 2y + 10 - 5
x = 2y + 5 ........................ equation 2
Equating equation 1 and 2 , we have
3y -6 = 2y + 5
add 6 to both sides
3y = 2y + 5 + 6
subtract 2y from both sides
3y - 2y = 11
y = 11
substitute y = 11 into equation 1 to find the value of x
x = 3y - 6
x = 3(11) - 6
x = 33 - 6
x = 27
This means that the father is presently 27 years and the son is presently 11 years.
In four years time
father = 27 + 4 = 31
son = 11 + 4 = 15
sum of their ages in four years time will be
31 + 15 = 46 years
Well 41 divided by 6 is 6.8333333333333 so you just need to subtract .833333333333
I hope this answered your question
Answer:
$2,400
Step-by-step explanation:
Ken intends to start a savings account
10% = leisure spending
This means 90% = Expenses for school
Let us represent the amount he must save as : x
Hence in other for him to have $2,160 in his savings account, the amount Ken must earn is calculated as:
90/100 × x = $2,160
Cross Multiply
90x = $2,160 × 100
x = ($2,160 × 100) ÷ 90
x =$2,400
Therefore, the amount Ken has to earn to have the amount needed for school is $2,400
Answer:
=12y+18
Step-by-step explanation:
=(3)(6+4y)
=(3)(6)+(3)(4y)
=18+12y
=12y+18
Answer:
The <u>sample proportion</u>, denoted by ^p, is given by the formula ^p= 
, where x is the number of individuals with a specified characteristic in a sample of n individuals.
Step-by-step explanation:
Sample proportion is used to determine sample mean, sample standard error and test the hypotheses about the population.
<em>sample mean</em> can be stated as p and <em>sample standard error</em> can be found using the equation
where
- p is the sample proportion
And if n×p×(1-p)≥10, then sample is assumed large enough to assume normal distribution and apply statistical test.
