Answer:
The answer is c
Step-by-step explanation:
I got this awnser from khan
Hello :
the normal vector of the plane is : d' = [4,-1,5]...(vector perpendicular to the plane)<span>
d </span><span>⊥ d' because : (4)(2)+(-1)(3)+(5)(1)=0
</span>the line is perpendicular to the plane .
2x - 3y = 6
-3y = -2x + 6
y = 2/3x - 2....the slope here is 2/3. A parallel line will have the same slope
y = mx + b
slope(m) = 2/3
(9,-3)...x = 9 and y = -3
now we sub and find b, the y int
-3 = 2/3(9) + b
-3 = 6 + b
-3 - 6 = b
-9 = b
so ur parallel equation is : y = 2/3x - 9 <== or 2x -3y = 27
Answer: -12
Step-by-step explanation: To solve this problem, we can first start by rewriting the problem. When we add a negative, that's exactly the same thing as subtracting so we can make the problem easier to understand.
18 + (-30) → 18 - 30
To find the answer to this problem, let's first find out how many jumps it get's to 0 from 18. It would take 18 jumps and there is 12 jumps left over. Then, we would subtract 12 from 0 and we would get -12 as our answer. Therefore, 18 + (-30) = -12.
