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eduard
3 years ago
10

Simplify the expression. (128x^5/ 8x)1/4 Enter your answer in the box.

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
7 0
To solve: 
Simplify 128x^5/8x first
16x^4

then divide by 1/4

16x^4•4/1=64x^4

Answer: 64x^4
katovenus [111]3 years ago
3 0

Answer:

2x^4 is the simplified expression

Step-by-step explanation:

We have been given an expression:

(\frac{128x^5}{8x})^\frac{1}{4}

First simplify the terms inside the parenthesis we divide 128 by 8 we get:

(16x^4)^\frac{1}{4}

16 can be written as 2^4 so the given terms become

((2^4)(x^4))^\frac{1}{4}

powers will get cancel because 4\cdot \frac{1}{4}=1 hence, we get:

2x^4 is the simplified expression.


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Find the measure of angle XAZ in the figure below.
Bess [88]

Answer:

m∠XAZ = 40°

Step-by-step explanation:

Since ∠YAU, ∠YAZ and ∠XAZ are the angles based at a point on a straight line, and the sum of the all angles on a line is 180°.

Therefore, m∠YAU + m∠YAZ + m∠XAZ = 180°

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2 years ago
Solve for x in the diagram below
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x = 15

Step-by-step explanation:

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3 years ago
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Use the laws of logarithms and the values given below to evaluate the logarithmic expression.
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3 years ago
Find the augmented matrix for each of the following systems of linear equations. (a) x₂ - 2x2 = 0 (6) x + x₃ = 1 .3x₂ + 4x2 = -1
Y_Kistochka [10]

Answer:

The augmented matrix for each set of linear equations is:

a) x_1-2x_2=0\\3x_1+4x_2=-1\\2x_1-x_2=3

Augmented matrix:

\left[\begin{array}{ccc}1&-2&0\\3&4&-1\\2&-1&3\end{array}\right]

b) x_1+x_3=1\\-x_1+2x_2-x_3=3

Augmented matrix:

\left[\begin{array}{cccc}1&0&1&1\\-1&2&-1&3\end{array}\right]

c) x_1+x_3=1\\2x_2-x_3+x_5=2\\2x_3+x_4=3

Augmented matrix:

\left[\begin{array}{cccccc}1&0&1&0&0&1\\0&2&-1&0&1&2\\0&0&2&1&0&3\end{array}\right]

d) x_1=1\\x_2=2

Augmented matrix:

\left[\begin{array}{ccc}1&0&1\\0&1&2\end{array}\right]

Step-by-step explanation:

In order to find the augmented matrix, you have to take the numeric values of each variable and make a matrix with them. For example, in the linear system a) you can make a matrix out of the numeric values accompanying x_1 and x_2, this matrix will be:  

\left[\begin{array}{cc}1&-2\\3&4\\2&-1\end{array}\right]

Then you have to make a vector with the constants in the linear equations, for the case of system a) the vector will be:  

\left[\begin{array}{c}0&-1&3\end{array}\right]

To construct the augmented matrix, you append those matrices together and create a new one:

\left[\begin{array}{ccc}1&-2&0\\3&4&-1\\2&-1&3\end{array}\right]

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