2 years ago

Write an equation to represent the following statement. 60 is 5 times as great as k

Mathematics

2 answers:

Eddi Din [679]2 years ago

5 0

60=5k
60/5=k
12=k
12=k is your answer, hope this helped :)

gizmo_the_mogwai [7]2 years ago

3 0

Answer:

60=5k

Step-by-step explanation:

k=12

I did it on Khan and got it right!

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At the fast pack shiping. The employees can unload 25 trucks in 5 hours which of the following is a correct unit rate for this s

Natasha2012 [34]

Answer:

5 trucks per hour

Step-by-step explanation:

25 trucks ÷ 5

5 hours ÷ 5

= 5 trucks per hour

3 0

3 years ago

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,