Answer:
The probability that more than 5 parolees out of 15 that return to prison within 3 years is 0.2784.
Step-by-step explanation:
The random variable X be the number of parolees that return to prison within 3 years.
The probability of occurrence of the random variable <em>X</em> is, <em>p</em> = 0.30.
A random sample of <em>n</em> = 15 prisoner are selected.
It is assumed that whether or not one prisoner returns to prison is independent of whether any of the others return to prison.
The random variable <em>X</em> follows a binomial distribution with parameters <em>n</em> = 15 and <em>p</em> = 0.30.
Compute the probability that more than 5 parolees out of 15 that return to prison within 3 years as follows:

![=1-\sum\limits^{5}_{0}{{15\choose x}(0.30^{x}(1-0.30)^{15-x}}\\\\=1-[0.00475+0.03052+0.09156+0.17004+0.21862+0.20613]\\\\=0.27838\\\\\approx 0.2784](https://tex.z-dn.net/?f=%3D1-%5Csum%5Climits%5E%7B5%7D_%7B0%7D%7B%7B15%5Cchoose%20x%7D%280.30%5E%7Bx%7D%281-0.30%29%5E%7B15-x%7D%7D%5C%5C%5C%5C%3D1-%5B0.00475%2B0.03052%2B0.09156%2B0.17004%2B0.21862%2B0.20613%5D%5C%5C%5C%5C%3D0.27838%5C%5C%5C%5C%5Capprox%200.2784)
Thus, the probability that more than 5 parolees out of 15 that return to prison within 3 years is 0.2784.