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WARRIOR [948]
3 years ago
13

In Texas, 30% of parolees from prison return to prison within 3 years.Suppose 15 prisoners are released from a Texas prison on p

arole. Assume that whether or not one prisoner returns to prison is independent of whether any of the others return to prison. Let the random variable X be the number of parolees out of 15 that return to prison within 3 years. What is the probability that more than 5 parolees out of 15 that return to prison within 3 years?
Mathematics
1 answer:
Arte-miy333 [17]3 years ago
5 0

Answer:

The probability that more than 5 parolees out of 15 that return to prison within 3 years is 0.2784.

Step-by-step explanation:

The random variable X be the number of parolees that return to prison within 3 years.

The probability of occurrence of the random variable <em>X</em> is, <em>p</em> = 0.30.

A random sample of <em>n</em> = 15 prisoner are selected.

It is assumed that whether or not one prisoner returns to prison is independent of whether any of the others return to prison.

The random variable <em>X</em> follows a binomial distribution with parameters <em>n</em> = 15 and <em>p</em> = 0.30.

Compute the probability that more than 5 parolees out of 15 that return to prison within 3 years as follows:

P(X>5)=1-P(X\leq 5)

               =1-\sum\limits^{5}_{0}{{15\choose x}(0.30^{x}(1-0.30)^{15-x}}\\\\=1-[0.00475+0.03052+0.09156+0.17004+0.21862+0.20613]\\\\=0.27838\\\\\approx 0.2784

Thus, the probability that more than 5 parolees out of 15 that return to prison within 3 years is 0.2784.

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I'm assuming the given function is f(x) = 15x^2 + 10x.

If so, then,

f(x) = 15x^2 + 10x
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Step-by-step explanation:

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3 years ago
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