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2 years ago

I will give brainliest to the correct answer. <3

Mathematics

2 answers:

aivan3 [116]2 years ago

7 0

i really dont wanna copy anyone so look at this link-

brainly.com/question/18499506

what they wrote was

dawn= x

erik= 1/3 x

jiro= 1/3 x -4

alita= 2(1/3 x -4)

x+x+ (1/3) x -4+2(1/3 x -4)=72

solmaris [256]2 years ago

5 0

dang all their ages is 72??!!!!!!

NAH IM joking

Step-by-step explanation:

You might be interested in

Find the following product 4x+5(4x-5)

sveticcg [70]

8x is the final answer.

4 0

3 years ago

Ryan and Sarah collect baseball cards. Ryan has 150 baseball cards and collects 10 cards per week. Sarah has 200 baseball cards

Nadusha1986 [10]

Answer:

<h2>10 weeks </h2>

Step-by-step explanation:

Step one:

given data

Ryan

number of baseball cards=150

number collected per week= 10

let the number of weeks be x

and the total be y

y=10x+150-----------------1

Sarah

number of baseball cards=200

number collected per week= 5

let the number of weeks be x

and the total be y

y=5x+200------------2

Step two:

Required

the number of weeks where both total will be the same

10x+150=5x+200

10x-5x=200-150

5x=50

divide both sides by 5

x=50/5

x=10 weeks

3 0

2 years ago

A what is an equation stating that two ratios or rates are equal

frozen [14]

The equation is
(A ≠ B)
A is the first number, ratio, rate, etc. , and B is the second.
The ≠ symbol means "does not equal", so the equation means:
[ Ratio A is NOT equal to Ratio B. ]

8 0

3 years ago

Explain how to get that answer!!

ra1l [238]

We need to simplify $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$

First lets factor $\sqrt{14x^3}$

$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$
$\sqrt{14} = \sqrt{2} \sqrt{7}$ by applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$
$\sqrt{x^3} = x^{3/2}$ By applying the radical rule $\sqrt[n]{x^m} = x^{m/n}$

So
$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$ = $\sqrt{2} \sqrt{7}x^{3/2}$

Now let's factor $\sqrt{18x}$
By applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$ ,
$\sqrt{18x} = \sqrt{18} \sqrt{x}$
$\sqrt{18} = \sqrt{2} * 3$

So $\sqrt{18x}$ = $\sqrt{2}*3 \sqrt{x}$

So $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x} }$

We know that $\sqrt[n]{x} = x^{1/n}$ so $\sqrt{x} = x^{1/2}$

We now have $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}} = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}}$

We know that $\frac{x^a}{x^b} = x^{a-b}$
So $\frac{x^{3/2}}{x^{1/2}} = x^{3/2 - 1/2} = x$

We now got $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}} = \frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3}
$

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:
$\frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3} = \frac{ \sqrt{7}x }{3}$

All in All, we get $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{7}x }{3}$

Hope this helps! :D

6 0

3 years ago

What is the answer and how would I solve this?

ipn [44]

Answer:

Step-by-step explanation:

The answere is no solution, there are no values of X that makes the inequality true, therefore there is no solution

7 0

3 years ago