Slope =
So taking 2 points (0,0) and (60,120)
we have slope = (120-0)/(60-0) = 120/60 = 2
general equation of linear graph is y=mx+b with m be the slope
so y=2x+b
Now to find b, just plug any point of the graph in, such as (0,0)
so we get something like 0=2(0) + b => b=0
So your equation is y=2x
Answer:
Chelsey can be a member of the fitness club for <u>10</u> months.
Step-by-step explanation:
Given:
Chelsey wants to join a fitness club.
The fitness club charges an initial membership fee of $55 and a monthly fee of $19.50.
She has $250 to spend on a membership at the fitness club.
Now, to find the number of months Chelsey can be a member of the fitness club.
Let the number of months Chelsey can be a member of the fitness club be
Monthly fee = $19.50.
Membership fee = $55.
Now, to get the number of months Chelsey can be a member of the fitness club we write and solve an equation:
<em>Subtracting both sides by 55 we get:</em>
<em>Dividing both sides by 19.50 we get:</em>
Therefore, Chelsey can be a member of the fitness club for 10 months.
a. Find the graph of their common region in the attachment
b. The area of the common region of the graphs is 8 units²
<h3>a. How to sketch the region common to the graphs?</h3>Since we have x ≥ 2, y ≥ 0, and x + y ≤ 6, we plot each graph separately and find their region of intersection.
So, the graph of x + y ≤ 6 is the region below the line y = - x + 6
From the graph, the regions intersect at (2, 0), (2, 4) and (6, 0)
Find the graph of their common region in the attachment
<h3>b. The area of the common region</h3>From the graph, we see that the common region is a right angled triangle with
So, its area = 1/2 × height × base
= 1/2 × 4 units × 4 units
= 1/2 × 16 units²
= 8 units²
So, the area of the common region of the graphs is 8 units²
Learn more about region common to graphs here:
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